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Do you use thermal energy every day?
Yes, your body uses a thermal energy known as caloric energy called "calories." A calorie is the amount of thermal energy required to heat one gram of water by one degree centigrade.
How long will it take 1 watt to heat 1 liter of water 1 degree centigrade?
Roughly 4200 seconds, since the specific heat of water is around 4.2J/gK (ie it takes 4.2 joules to raise 1 gram by 1 Kelvin); 1 litre = 1000 grams, 1 Celcius (centigrade) = 1K, 1W = 1J/s.
How much heat is added when 22 grams of water are heated from 10 degreesC to 15 degrees C?
(110 calories) plus (heat lost from the container during the procedure)
How many watts are required to heat one gallon of water one degree?
2.4705 watts/hour
How many calories to raise 1 quart of water 38 degrees?
A quart of water is 946.35 cubic centimeters and since density of water is 1 gram per cubic centimeter the weight of a quart of water is 946.35 grams. Heat required = (mass) x (specific heat of substance) x (temperature differential) In our case it would be 946.35 x 1 x 38(assumed degrees centigrade) = 35961.3 cals
If you have a 2 liter bottle of liquid water at 0 Celsius. About how many Calories are needed to heat up the water to 100 C?
It takes 1 calorie to heat 1 gram of water by 1 degree Celsius. A 2 liter bottle of water weighs around 2000 grams. Therefore, you would need 200,000 calories to heat the water from 0 to 100 degrees Celsius.
How many calories are there in a litre of water?
Nutritionally, none at all. If you are talking about calories as in weight loss and diet, water hasn't got any calories. Thermodynamically, the calorie as a unit of energy is deprecated in favor of the Joule. It takes 1000 calories (or one kilocalorie, also known as one Calorie) to raise the temperature of 1000 g of water one degree C. Because 1 kg of water is approximately one liter, you can get one Calorie (1000 calories) of heat energy per degree C from a liter of hot water as it cools. (Recovering that heat as usable energy is a different matter entirely.)
How many watts to heat 1 liter of water?
It takes about 4.18 Joules of energy to heat 1 gram of water by 1 degree Celsius. Therefore, to heat 1 liter (1000 grams) of water by 1 degree Celsius, it would require about 4180 Joules. Converting this to watts depends on the time taken to heat the water.
How many calories are needed to heat 1 liter of water by 1 degree?
200000 calories. 1 gm of water needs 1 cal(calorie) to raise it's temperature through 10C. Now, density of water = 1gm/ml at 40C and we assume that it's density is same at 00C. So we have 2000gm of water. For raising temp by 10C we need 2000 cal. For raising temp by 1000C we need 2000 x 100 cal = 200000 calories
How much heat is required to raise 2 grams of water 1 degree C?
The answer is 2 calories.
How much energy is required to raise the temperature of one liter of water 1 degree centigrade?
The specific heat of water is 4.179 Joules per gram per degree Centigrade. The density of water is 1 gram per cubic centimeter, so one liter is 1000 grams. This means it takes 4179 Joules to raise one liter one degree Centigrade.
How much heat does it take to heat 1 liter of water from 20 to 80 degrees?
The calorific value of water is 80cal/degree. so it takes 60*80=2400cal of heat.
How many kw are needed to heat 1 liter of water 1 degree?
1 litre for 1 degree in 1hour is 1,16 kW/h
How much heat is needed to heat 100g of water from 10 to 95 degrees?
A calorie of energy (NOT to be confused with a Calorie, they are different so watch the caps) is the amount necessary to heat 1 gram of water 1oC, so 30 calories are needed to heat 30 g of water 1 degree. To heat it 70oC would take 2100 calories (or 2.1 Calories) of energy.
How many calories would it take to heat up Lake Michigan by 1 degree Celsius?
To calculate the calories required to heat up Lake Michigan by 1 degree Celsius, you would need to know the specific heat capacity of water (4.186 J/g°C) and the mass of water in Lake Michigan. The formula to calculate the energy required is: Energy = mass of water x specific heat capacity of water x change in temperature. This would give you the calories needed to heat up Lake Michigan by 1 degree Celsius.
How many calories does it take to heat 0.373 liter of water 30 C?
It takes 1 kcal to raise the temperature of 1 kg of water by 1 degree C. To do this accurately, you need the temperature of the water to determine its density, but for the sake of simplicity, we'll use its value at 4oC, which is 1 g/ml 373 ml is equal to 373g or 0.373kg. Therefore, for that volume of water it should take 0.373 kcal per degree C., so 0.373 x 30 = 11.19 kcal, or 11,190 cal
How much heat is required to evaporate 1 liter of water at 100 degree celsius?
The heat required to evaporate 1 liter of water at 100 degrees Celsius is known as the latent heat of vaporization of water, which is approximately 2260 kJ/kg. Since the density of water is about 1000 kg/m³, the heat required would be around 2260 kJ.
