456,976,000
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10,108,800 assuming that leading 0s are not allowed in the 3-digit numbers; that the licence authorities do not block some letter combinations because they are rude, and letters that might be confused with numbers (O and 0, I and 1, Z and 2, S and 5, B and 8) are all permitted.
First of all, There are 10 Different numbers, 0-9. And 26 Letters, A-Z. We want 3 of there numbers. so it is, 10P3= 720 (10!/7!) We also want 26P4 =358800 So the Answer is 358800*720=258336000. Which is 258Million 336 Thousand. Roughly. As Some letters may not be used or some numbers. I don't really know the working of license plates. Update: Assuming that you are allowing repetitions of both letters and numbers, it follows that you do not have to use (p(n,r)) to find the permutation. The correct calculation is: 10^3(26^4) or p= 10*10*10(26*26*26*26)= 456,976,000
If it alternates and you start with a letter, then there are 11,232,000 permutations. Then if you start with a number and alternate, there are another 11,232,000 permutations, for a total of 22,464,000 permutations. If you exclude the letters I, S, B, and O (because they look kind-of like 1, 5, 8, & 0 - kind-of important on license plates) then you are down to 6,652,800 & 13,305,600 respectively.
each of the four numbers have 10 possibilities, and each of the three letters have 26 possibilities. so the total possible ways u can arrange them are 10x10x10x10x26x26x26 this totals up to 175,760,000 different license plate numbers
When you spell out the words for numbers 1-10 four of the numbers have three letters. (one two six ten)