456,976,000
To calculate the number of different seven-character license plates where the first four characters are letters and the last three are numbers, we consider the following: There are 26 letters in the English alphabet, so for the first four positions, there are (26^4) combinations. For the last three positions, which are numbers (0-9), there are (10^3) combinations. Therefore, the total number of different license plates is (26^4 \times 10^3).
10,108,800 assuming that leading 0s are not allowed in the 3-digit numbers; that the licence authorities do not block some letter combinations because they are rude, and letters that might be confused with numbers (O and 0, I and 1, Z and 2, S and 5, B and 8) are all permitted.
First of all, There are 10 Different numbers, 0-9. And 26 Letters, A-Z. We want 3 of there numbers. so it is, 10P3= 720 (10!/7!) We also want 26P4 =358800 So the Answer is 358800*720=258336000. Which is 258Million 336 Thousand. Roughly. As Some letters may not be used or some numbers. I don't really know the working of license plates. Update: Assuming that you are allowing repetitions of both letters and numbers, it follows that you do not have to use (p(n,r)) to find the permutation. The correct calculation is: 10^3(26^4) or p= 10*10*10(26*26*26*26)= 456,976,000
If it alternates and you start with a letter, then there are 11,232,000 permutations. Then if you start with a number and alternate, there are another 11,232,000 permutations, for a total of 22,464,000 permutations. If you exclude the letters I, S, B, and O (because they look kind-of like 1, 5, 8, & 0 - kind-of important on license plates) then you are down to 6,652,800 & 13,305,600 respectively.
each of the four numbers have 10 possibilities, and each of the three letters have 26 possibilities. so the total possible ways u can arrange them are 10x10x10x10x26x26x26 this totals up to 175,760,000 different license plate numbers
There are 676,000 ways to make the license plates.
To calculate the number of different seven-character license plates where the first four characters are letters and the last three are numbers, we consider the following: There are 26 letters in the English alphabet, so for the first four positions, there are (26^4) combinations. For the last three positions, which are numbers (0-9), there are (10^3) combinations. Therefore, the total number of different license plates is (26^4 \times 10^3).
There are 17,576 possible license plates. There are 26 possible letters in the first space times 26 in the second space times 26 in the third space.
263 x 98 (assuming "00" is not used) ie 1,722,448
35,152,000 (assuming that 000 is a valid number, and that no letter combinations are disallowed for offensive connotations.) Also, no letters are disallowed because of possible confusion between letters and numbers eg 0 and O.
Multiply the possibilities for each digit: 26 * 26 * 26 * 10 * 10 * 10 = 17,576,000
10,108,800 assuming that leading 0s are not allowed in the 3-digit numbers; that the licence authorities do not block some letter combinations because they are rude, and letters that might be confused with numbers (O and 0, I and 1, Z and 2, S and 5, B and 8) are all permitted.
In California, for example, the first digit of a standard plate is a number, followed by 3 letters, and then three numbers. There are 26 letters in the alphabet, so there are 26 raised to the 3rd power combinations, or 26 * 26 * 26, which is 17,576 possibilities just of the 3 letters.
Oh, dude, in Toontown, license plates are like the VIP passes for the wacky road trips. With three letters followed by a digit from 1 to 9, you've got a total of 26 letters in the alphabet and 9 digits to choose from. So, the total number of possible license plates would be 26 * 26 * 26 * 9, which is like a whole lot of crazy combos - 15,429,600 to be exact. So buckle up and enjoy the ride, Toontown style!
First of all, There are 10 Different numbers, 0-9. And 26 Letters, A-Z. We want 3 of there numbers. so it is, 10P3= 720 (10!/7!) We also want 26P4 =358800 So the Answer is 358800*720=258336000. Which is 258Million 336 Thousand. Roughly. As Some letters may not be used or some numbers. I don't really know the working of license plates. Update: Assuming that you are allowing repetitions of both letters and numbers, it follows that you do not have to use (p(n,r)) to find the permutation. The correct calculation is: 10^3(26^4) or p= 10*10*10(26*26*26*26)= 456,976,000
If it alternates and you start with a letter, then there are 11,232,000 permutations. Then if you start with a number and alternate, there are another 11,232,000 permutations, for a total of 22,464,000 permutations. If you exclude the letters I, S, B, and O (because they look kind-of like 1, 5, 8, & 0 - kind-of important on license plates) then you are down to 6,652,800 & 13,305,600 respectively.
each of the four numbers have 10 possibilities, and each of the three letters have 26 possibilities. so the total possible ways u can arrange them are 10x10x10x10x26x26x26 this totals up to 175,760,000 different license plate numbers