There are 900 natural numbers made up of only three digits. This is because there are 9 options for the first digit (1-9), 10 options for the second digit (0-9), and 10 options for the third digit (0-9). Multiplying these options together gives us 9 x 10 x 10 = 900 possible three-digit natural numbers.
Assuming you are treating each number as a number and not as an individual unit, the numbers you can make from these digits are 899, 989 and 998.
32C3 = 4960
9,752 9,725 9,572
45
-4309278
depends on your answer
Assuming you mean permutations of three digits, then the set of numbers that can be made with these digits is: 345 354 435 453 534 543 There are six possible permutations of three numbers.
6
1
Assuming you are treating each number as a number and not as an individual unit, the numbers you can make from these digits are 899, 989 and 998.
32C3 = 4960
24 three digit numbers if repetition of digits is not allowed. 4P3 = 24.If repetition of digits is allowed then we have:For 3 repetitions, 4 three digit numbers.For 2 repetitions, 36 three digit numbers.So we have a total of 64 three digit numbers if repetition of digits is allowed.
9,752 9,725 9,572
45
-4309278
The digits of 345 are 3, 4, and 5. To form a two-digit number, we can choose any of the three digits for the tens place and any of the three digits for the units place. However, since a two-digit number cannot start with 0 and all three digits are non-zero, we can use all three digits. Thus, we have 3 choices for the first digit and 3 choices for the second digit, resulting in (3 \times 3 = 9) two-digit numbers.
All numbers are made with digits and there is no limit on how big they can be. So there is no greatest number.