46 x 45 x 44 x 43 x 42 x 41 = 6,744,109,680
* * * * *
That is the number of permutations. The number of combinations - where the order of the number does not matter (eg in a lottery) - is
46*45*44*43*42*41/(6*5*4*3*2*1) = 9,366,819
There are infinitely many numbers and so infinitely many possible combinations.
In a 7 segment display, the symbols can be created using a selected number of segments where each segment is treated as a different element.When 1 segment is used, the possible positions are 7because it can be any of the 7 segments (7C1=7).When 2 segments are used, the number of possible combinations are 7C2=21.When 3 segments are used, the number of possible combinations are 7C3=35When 4 segments are used, the number of possible combinations are 7C4=35When 5 segments are used, the number of possible combinations are 7C5=21When 6 segments are used, the number of possible combinations are 7C6=7When 7 segments are used, the number of possible combinations are 7C7=1Adding the combinations, 7+21+35+21+7+1=127Therefore, 127 symbols can be made using a 7 segment display!
There are twelve possible solutions using the rule you stated.
There is only 1 combination.
The question is incorrect since there are 210 - 1 possible combinations. The digit 0 can be in the combination or out. That gives 2 ways. With each, the digit 1 can be in the combination or out - 2*2 = 22 ways. With each, the digit 2 can be in the combination or out = 23 ways. With each, the digit 3 can be in the combination or out = 24 ways. etc. So 210 ways in all except that one of them is the null combination. Now 210 = 1024 so there are only 1023 combinations. If, instead, you allow the digits to be used many times, there is no limit to the number of combinations.
128
There are infinitely many numbers and so infinitely many possible combinations.
140 possible combinations
If you can repeat the numbers within the combination there are 10,000 different combinations. If you cannot repeat the numbers within the combination, there are 5040 different combinations.
In a 7 segment display, the symbols can be created using a selected number of segments where each segment is treated as a different element.When 1 segment is used, the possible positions are 7because it can be any of the 7 segments (7C1=7).When 2 segments are used, the number of possible combinations are 7C2=21.When 3 segments are used, the number of possible combinations are 7C3=35When 4 segments are used, the number of possible combinations are 7C4=35When 5 segments are used, the number of possible combinations are 7C5=21When 6 segments are used, the number of possible combinations are 7C6=7When 7 segments are used, the number of possible combinations are 7C7=1Adding the combinations, 7+21+35+21+7+1=127Therefore, 127 symbols can be made using a 7 segment display!
There are 210 4 digit combinations and 5040 different 4 digit codes.
There are twelve possible solutions using the rule you stated.
There are only 10 combinations. In each combination one of the 10 digits is left out.
To calculate the number of possible combinations for the number 24680 using each number only once, we can use the formula for permutations. There are 5 numbers to arrange, so the number of permutations is 5! (5 factorial), which is equal to 5 x 4 x 3 x 2 x 1 = 120. Therefore, there are 120 possible combinations for the number 24680 using each number only once.
im assuming that any charcter can be a number or a letter: (24letters*10 possible numbers)^(4 digits)= 3317760000 possible combinations.
If the digits can repeat, then there are 256 possible combinations. If they can't repeat, then there are 24 possibilities.
There is only 1 combination.