46 x 45 x 44 x 43 x 42 x 41 = 6,744,109,680
* * * * *
That is the number of permutations. The number of combinations - where the order of the number does not matter (eg in a lottery) - is
46*45*44*43*42*41/(6*5*4*3*2*1) = 9,366,819
There are infinitely many numbers and so infinitely many possible combinations.
In a 7 segment display, the symbols can be created using a selected number of segments where each segment is treated as a different element.When 1 segment is used, the possible positions are 7because it can be any of the 7 segments (7C1=7).When 2 segments are used, the number of possible combinations are 7C2=21.When 3 segments are used, the number of possible combinations are 7C3=35When 4 segments are used, the number of possible combinations are 7C4=35When 5 segments are used, the number of possible combinations are 7C5=21When 6 segments are used, the number of possible combinations are 7C6=7When 7 segments are used, the number of possible combinations are 7C7=1Adding the combinations, 7+21+35+21+7+1=127Therefore, 127 symbols can be made using a 7 segment display!
There are twelve possible solutions using the rule you stated.
The number of possible combinations using 4 distinct numbers depends on whether the order matters and whether repetitions are allowed. If order does not matter and repetitions are not allowed, the number of combinations of 4 numbers chosen from a larger set can be calculated using the combination formula (C(n, r) = \frac{n!}{r!(n-r)!}), where (n) is the total number of numbers available. If order matters, you would use permutations instead. Please specify if you need combinations with or without repetitions and whether order matters for a more precise answer.
There is only 1 combination.
128
There are infinitely many numbers and so infinitely many possible combinations.
140 possible combinations
If you can repeat the numbers within the combination there are 10,000 different combinations. If you cannot repeat the numbers within the combination, there are 5040 different combinations.
In a 7 segment display, the symbols can be created using a selected number of segments where each segment is treated as a different element.When 1 segment is used, the possible positions are 7because it can be any of the 7 segments (7C1=7).When 2 segments are used, the number of possible combinations are 7C2=21.When 3 segments are used, the number of possible combinations are 7C3=35When 4 segments are used, the number of possible combinations are 7C4=35When 5 segments are used, the number of possible combinations are 7C5=21When 6 segments are used, the number of possible combinations are 7C6=7When 7 segments are used, the number of possible combinations are 7C7=1Adding the combinations, 7+21+35+21+7+1=127Therefore, 127 symbols can be made using a 7 segment display!
There are 210 4 digit combinations and 5040 different 4 digit codes.
There are twelve possible solutions using the rule you stated.
There are only 10 combinations. In each combination one of the 10 digits is left out.
To calculate the number of possible combinations for the number 24680 using each number only once, we can use the formula for permutations. There are 5 numbers to arrange, so the number of permutations is 5! (5 factorial), which is equal to 5 x 4 x 3 x 2 x 1 = 120. Therefore, there are 120 possible combinations for the number 24680 using each number only once.
im assuming that any charcter can be a number or a letter: (24letters*10 possible numbers)^(4 digits)= 3317760000 possible combinations.
If the digits can repeat, then there are 256 possible combinations. If they can't repeat, then there are 24 possibilities.
There is only 1 combination.