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The number of possible combinations using 4 distinct numbers depends on whether the order matters and whether repetitions are allowed. If order does not matter and repetitions are not allowed, the number of combinations of 4 numbers chosen from a larger set can be calculated using the combination formula (C(n, r) = \frac{n!}{r!(n-r)!}), where (n) is the total number of numbers available. If order matters, you would use permutations instead. Please specify if you need combinations with or without repetitions and whether order matters for a more precise answer.

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5d ago

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