0
Oh, dude, you're making me do math now? Alright, so if you have three numbers and you're asking how many combinations you can make with those three numbers, it's like a little math puzzle. Each number can be used multiple times, so it's like a little party for those numbers. The total number of combinations you can make with three numbers is 27. That's like having 27 different outfits to choose from for a night out, but with numbers.
Still curious? Ask our experts.
Chat with our AI personalities
Steve
Taiga
DevinWell, honey, if you're talking about a three-digit number where each digit can be any number from 0 to 9, then there are 1,000 possible combinations. But if you're talking about a three-digit number where each digit has to be the same number, then there are only 10 possible combinations (111, 222, 333, and so on). Hope that clears things up for ya!
The number of combinations possible with the same three numbers can be calculated using the formula for combinations. If the numbers can be repeated, the formula is n^r, where n is the number of options for each digit and r is the number of digits. So, if each digit has 10 options (0-9) and there are 3 digits, there would be 10^3 = 1000 possible combinations.
Add your answer:
Earn +20 pts
How many number combinations are possible with three numbers?
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
How many arrangements of numbers is possible?
There are an infinite number of possibilities based on the infinite set of numbers. However, for a finite set, there are limited possible combinations, depending on whether you can use the same numbers over again, or if they have to be distinct, or if their order makes any difference. Here's an example: For a group of THREE numbers, there is only one possible group of 3 numbers, and there are three possible groups of 2 numbers (i.e. 12, 13, 23) . Using each of three different numbers, there are 6 ordered combinations of two numbers (12, 13, 23, 21, 31, 32) and 6 possible combinations of three numbers (123, 132, 213, 231, 312, 321). If the numbers are allowed to repeat, there are 9 possible combinations of two (add 11, 22, 33) and 8 more possible combinations of three (111, 112, 113, 122, 133, 222, 223, 333) - if order matters, each triple (111) has only one possible order, each double has three (112, 121, 211). The number rapidly increases for larger numbers of possible and larger groups from those sets. The possibilities are called combinations and permutations, and are connected to the numerical property called "factorials" (a number multiplied by all smaller integers - 2 factorial is represented by "2!" and equals 2 x 1 = 2, while 3! = 3 x 2 x 1 = 6). The number of discrete sets of K numbers from N possible numbers is N! / K! x (N-K)!
What are the odds of getting a sum divisible by three by rolling 2 dice?
If you have 12 possible numbers with multiple combinations then you should start out with making all the possible combinations; you will find theyre 20. Theyre four numbers out of the twleve that can be divisible by three; 3, 6, 9, and 12. There are 7 combinations where the combinations can equal those four numbers. So the odds of getting a sum divisible by three is 7/20.
What three prime numbers equal 18?
Three possible combinations: 17+1, 13+5 and 7+11.
What are the combinations of 1 through 10 with out using them twice?
There is 1 combination of all ten numbers, 10 combinations of one number and of nine numbers, 45 combinations of two or eight numbers, 120 combinations of three or seven numbers, 210 combinations of four or six numbers and 252 combinations of five numbers. That is 1023 = 210 - 1 in total.
