You can make 6 combinations with 3 numbers. They are:
123 213 312
132 231 321
* * * * *
NO! Those are permutations! In combitorials, the order does not matter so that the combination 123 is the same as the combination 132 etc. So all of the above comprise just 1 combination.
With three numbers you can have
1 combination of three numbers (as discussed above),
3 combinations of 2 numbers (12, 13 and 23)
3 combinations of 1 number (1, 2 and 3)
In all, with n numbers you can have 2n - 1 combinations. Or, if you allow the null combination (that consisting of no numbers) you have 2n combinations.
1000
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
You could make 10*10*10*26*26*26 combinations, or 17576000 combinations.
Only one.
There are 167960 combinations.
1000
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
Using the combination fuction, chose three numbers from 45 numbers. The answer is 14,190.
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
20,3,10 or 12,5,10 there are many combinations of numbers
6
16.65
5
Assuming you are treating each number as a number and not as an individual unit, the numbers you can make from these digits are 899, 989 and 998.
You could make 10*10*10*26*26*26 combinations, or 17576000 combinations.
If you are using three distinct numbers and want to find the number of different combinations that can be formed, you would consider the combinations of those numbers. For three numbers, the combinations can be represented as C(3, k) for k = 1 to 3. Thus, the total combinations are 3 (for k=1) + 3 (for k=2) + 1 (for k=3), resulting in a total of 7 unique combinations.
3! or 6 combinations can be made from three distinct numbers. For this example they are: 345, 354, 534, 543, 435, 453.