i have the same question. please some1 answer it...
there are 4 numbers
There are 24 different arrangements of 4 numbers (4 factorial or 4!). If you allow numbers to be repeated then the figure becomes 256 (44)
4
from the numbers 4567 we can have 24 numbers
Every bit can be either 0 or 1. Therefore 4 bits can encode a maximum of 42 = 16 digits.
i have the same question. please some1 answer it...
how many combinations of 4 numbers are there in 7 numbers
Using 4 bits the signed range of numbers is -8 to 7. When working with signed numbers one bit is the sign bit, thus with 4 bits this leaves 3 bits for the value. With 3 bits there are 8 possible values, which when using 2s complement have ranges: for non-negative numbers these are 0 to 7; for negative numbers these are -1 to -8. Thus the range for signed 4 bit numbers is -8 to 7.
there are 4 numbers
There are infinitely many numbers between 34 and 50 and so infinitely many sets of 4 numbers.
With 4 different numbers, 24.
A nibble is 4 bits, so there are 1/4 (or 0.25) nibbles in a bit.
There are 24 different arrangements of 4 numbers (4 factorial or 4!). If you allow numbers to be repeated then the figure becomes 256 (44)
addresses are 32-bit numbers often expressed as 4 octets in "dotted decimal" notation (for ... Internet Corporation for Assigned Names and Numbers ...
10 * * * * * That is just plain wrong! It depends on how many numbers in each combination but there are 1 combination of 4 numbers out of 4, 4 combinations of 3 numbers out of 4, 6 combinations of 2 numbers out of 4, 4 combinations of 1 number out of 4. A grand total of 15 (= 24-1) combinations.
When the repetition is allowed: 4*4*4 = 64 numbers. Without repetition: 4*3*2 = 24 numbers.