Including leading zeroes, the answer is 720. If you don't include leading zeroes, then 600.
1,956 different numbers can be made from 6 digits. You can calculate this by using the permutation function in a summation function, like this: Σ6k=1 6Pk = 6P1+6P2+...+6P5+6P6 What this does is calculate how many 1 digit numbers you can make from 6 digits, then how many 2 digit numbers can be made from 6 digits and adds the amounts together, then calculates how many 3 digit numbers can be made and adds that on as well etc.
256!
8
Using 1, 2, and 3, you can make 27 whole numbers.
Including leading zeroes, the answer is 720. If you don't include leading zeroes, then 600.
1,956 different numbers can be made from 6 digits. You can calculate this by using the permutation function in a summation function, like this: Σ6k=1 6Pk = 6P1+6P2+...+6P5+6P6 What this does is calculate how many 1 digit numbers you can make from 6 digits, then how many 2 digit numbers can be made from 6 digits and adds the amounts together, then calculates how many 3 digit numbers can be made and adds that on as well etc.
First we'll find out how many combinations are possible if zero was another integer. In the ten thousands place, there are six possible numbers. In the thousands place, there are five possible, hundreds four, tens three, ones two.6! = 6 × 5 × 4 × 3 × 2 = 720 possible combinationsThere are 720 combinations of six different digits, but some of those possibilities have zero as the first number, in which case you've made a four-digit number. So now we need to find how many four digit numbers can be made with the digits 650271. The first digit can only have one possibility (zero). The second digit can have 5 possible, the third 4, the fourth 3, the fifth 2.1 × 5 × 4 × 3 × 2 = 120720 - 120 = 600
You can make 12 different numbers.
24 numbers
12 numbers
98
To make whole numbers. The numbers 1,2,4,17,34,68. So 6 numbers.
With 4 different numbers, 24.
256!
8
Using 1, 2, and 3, you can make 27 whole numbers.