10,000. from 0000 to 9999.
10,000 of them, from 0000 to 9999. However, most people would not count numbers with leading 0s, so that there would be 9000 4-digit numbers.
If leading zeros are allowed, then you have 0000 through 9999 which is 10,000 numbers.If leading zeros not allowed: the smallest four-digit number is 1000, eliminating 0000 through 0999 (one thousand numbers are not allowed), so it is 9,000 numbers.
Specify whether you are including the numbers between 0000 and 1000.
10000 ; This may look to be wrong but you can have 0001 to 9999 which gives you 9999 different combinations of 4 digits, plus another one for 0000.
4000 of them.
If you count 0000 to 9999 you have 10,000. For whole numbers you have 9999. * * * * * Not sure about "whole" numbers. There are 10,000 in all, of which 9000 (from 1000 to 9999) do not have leading 0s.
Not sure about the exact number but it is approx 1086.
10,000. from 0000 to 9999.
In base ten, there are 9000 four digit number, the numbers are from 1000 to 9999. If you allow leading zeros, then there are 10000 numbers. [0000 - 9999]
10^4 or 10,000, assuming that 0000 is a valid number. 0000, 0001, 0002, ..., 9997, 9998, 9999.
10000. 0000 to 9999
If by "between" you mean "between but not including", then the answer is 9999 - 999 - 1 = 8999.If on the other hand, you mean to include both 9999 and 999, then the answer is 9999 - 999 + 1 = 9001.
10,000 of them, from 0000 to 9999. However, most people would not count numbers with leading 0s, so that there would be 9000 4-digit numbers.
3439
WHOLE NUMBERS...The numbers (integers or whole numbers) between two numbers would not include the two numbers, so 9999 - 2 = 9997. Subtract 2 for the numbers 0001 and 9999.Another AnswerThe answer is infinity. If you ask unqualified questions, expect infinite answers.
There are 10000 because there is 0001 to 9999 and then there is 0000.