answersLogoWhite

0


Best Answer

7043.......there are 4 digits.

In 'normal' numbers that are greater than zero then zero is superfluous as the first digit, for example we write 437 NOT 0437.

Then, there are 3 possible numbers for the 1st digit (3, 4, 7) and 4 numbers for the 2nd, 3rd and 4th digits.(0,3,4,7).

The number of valid number combinations is, 3 x 4 x 4 x 4 = 192.

User Avatar

Wiki User

13y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How many numeric combinations could you obtain using the numbers 7043?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

Could you generate a complete set of 6 number combinations from 45 numbers?

Could you generate a complete set of 6 number combinations from 45 numbers ?


2 dice each dice has 6 numbers how many combinations could there be?

There are 21 combinations.


What are two numbers if the difference is 21?

There are an infinite number of combinations where this could be the answer.


How many combinations can you make out of 3 letters and 3 numbers?

You could make 10*10*10*26*26*26 combinations, or 17576000 combinations.


What 6 numbers have a mean of 18.5?

There is no single answer to that. A lot of combinations of 6 numbers could have a mean of 18.5, as any 6 numbers that add to 111 could.


What 3 numbers add up to 33?

36


What Program that lists telephone numbers in numeric order or street address?

In programming this could be achieved using a numeric bubble sort. Excel allows this type of sorting to be used.


5 dice each dice has 6 numbers how many combinations could be?

163759438475047695685695034395784593850835943859458474836937657 i have just tried it


How many possible combinations could be constructed using 3 letters and 3 numbers for a license plate?

To calculate the total number of possible combinations for a license plate using 3 letters and 3 numbers, we need to multiply the number of options for each character position. For letters, there are 26 options (A-Z), and for numbers, there are 10 options (0-9). Therefore, the total number of combinations can be calculated as 26 (letters) * 26 (letters) * 26 (letters) * 10 (numbers) * 10 (numbers) * 10 (numbers) = 17,576,000 possible combinations.


If you have a set of 40 numbers how do you calculate the number of all the possible combinations of 5 numbers from the set?

By making a number tree that could have as many as 1,000,000 combos.


4 dice each dice has 6 numbers how many combinations could there be?

6^4 = 1296 combinations but some are repeatable e.g. 1221 = 2121 = 2112 etc. so for the total number of non repeatable combinations with 4 dice, use pascals triangle to get 126 unique combinations.


What two prime numbers added is 84?

There are several combinations of prime numbers that could have a sum of 84:11 and 7313 and 7117 and 6723 and 6131 and 5337 and 4741 and 43