To calculate the number of combinations of 5 numbers possible from 1 to 20, we use the formula for combinations, which is nCr = n! / (r!(n-r)!). In this case, n = 20 and r = 5. Plugging these values into the formula, we get 20! / (5!(20-5)!) = 20! / (5!15!) = (20x19x18x17x16) / (5x4x3x2x1) = 15,504 possible combinations.
There are many possible solutions. One of these is {7, 17, 17, 17, 17}
It depends how many numbers are in your combinations: 0 or 24 there is 1 1 or 23 there are 24 2 or 22 there are 276 3 or 21 there are 2,024 4 or 20 there are 10,626 5 or 19 there are 42,504 6 or 18 there are 134,596 7 or 17 there are 346,104 8 or 16 there are 735,471 9 or 15 there are 1,307,504 10 or 14 there are 1,961,256 11 or 13 there are 2,496,144 12 there are 2,704,156 If by combinations you do not mean the mathematical selection of a subset of items from a set of items (where the order doesn't matter) but how many ways are there of arranging 24 numbers then there are: 24! = 620,448,401,733,239,439,360,000 ways.
Well, isn't that a happy little question! There are many ways we can make 34 by adding numbers together. For example, 17 + 17 equals 34, or we could also say 10 + 24 equals 34. Just like in painting, there are many possibilities and combinations to create something beautiful.
17 of them. 17 of them. 17 of them. 17 of them.
Formula: nPr where n is the number of things to choose from and you choose r of them 17P3 = 17!/ (17-3)! = 4080
If they can repeat, then: 17^6=24,137,569 If they can't repeat, then: 17*16*15*14*13*12=8,910,720
There are 17 I think
Three possible combinations: 17+1, 13+5 and 7+11.
To calculate the number of combinations of 5 numbers possible from 1 to 20, we use the formula for combinations, which is nCr = n! / (r!(n-r)!). In this case, n = 20 and r = 5. Plugging these values into the formula, we get 20! / (5!(20-5)!) = 20! / (5!15!) = (20x19x18x17x16) / (5x4x3x2x1) = 15,504 possible combinations.
017, 071, 107, 170, 701, 710. 6 combinations
There are many possible solutions. One of these is {7, 17, 17, 17, 17}
There are 18C4 = 18!/[18-4)!4!] = 18*17*16*15/(4*3*2*1) = 3060 combinations.
Assuming you are using "combinations" in the mathematical sense where order doesn't matter (if order does matter it would be "permutations"), there are 22C5 = 22!/5!17! = 26,334 possible combinations of 5 numbers from 22. They start {1, 2, 3, 4, 5}, {1, 2, 3, 4, 6}, {1, 2, 3, 4, 7}, ... and end ... {16, 19, 20, 21, 22}, {17, 19, 20, 21, 22}, {18, 19, 20, 21, 22}; I'll leave the 26,328 combinations in the middle for you to list.
The first number has 19 possibilities. The second has 18, and the third only 17. 19x18x17=5814 possible lock combinations. (If you could repeat, it would be 19x19x19=6859)
There are infinitely many possible answers. One such is 3.45 + 2.59 + 10.96 = 17
21