Using the extended fundamental counting principle, you multiply the total number of options in each space together. There are 10 possible numbers for each of the three number spots, so you would do 10x10x10=1,000. Multiply this by 26 and 26 again for all the possible letters that can go in each letter spot: 1,000x26x26=676,000 So you have 676,000 possible license plate combinations.
384,475,000 license plates. There are 35 different letter/number combinations possible. Each combination has 10,985,000 variants. 35*10,985,000 = 384,475,000
35,152,000 (assuming that 000 is a valid number, and that no letter combinations are disallowed for offensive connotations.) Also, no letters are disallowed because of possible confusion between letters and numbers eg 0 and O.
Any three letters, in any order, including repeated letters gives 263 combinations each of which could have one of 9 digits so 26 x 26 x 26 x 9 ie 158184 different plates.
it 26 to the power 4 and then 99 for the numbers figure that out add the two together
Using the extended fundamental counting principle, you multiply the total number of options in each space together. There are 10 possible numbers for each of the three number spots, so you would do 10x10x10=1,000. Multiply this by 26 and 26 again for all the possible letters that can go in each letter spot: 1,000x26x26=676,000 So you have 676,000 possible license plate combinations.
There are 26 possible letters and 10 possible numbers. The number of license plates possible is then 26*26*10*10*10*10 = 6760000.
384,475,000 license plates. There are 35 different letter/number combinations possible. Each combination has 10,985,000 variants. 35*10,985,000 = 384,475,000
If you assume 26 different letters, there are 26 to the power 5 possible variations of 5 letters.
35,152,000 (assuming that 000 is a valid number, and that no letter combinations are disallowed for offensive connotations.) Also, no letters are disallowed because of possible confusion between letters and numbers eg 0 and O.
There are 17,576 possible license plates. There are 26 possible letters in the first space times 26 in the second space times 26 in the third space.
Any three letters, in any order, including repeated letters gives 263 combinations each of which could have one of 9 digits so 26 x 26 x 26 x 9 ie 158184 different plates.
In California, for example, the first digit of a standard plate is a number, followed by 3 letters, and then three numbers. There are 26 letters in the alphabet, so there are 26 raised to the 3rd power combinations, or 26 * 26 * 26, which is 17,576 possibilities just of the 3 letters.
If I understand correctly the first number has to be '1', the next three digits have to be letters, and the last digit can't be '0', so there are1x26x26x26x10x10x9 = 15,818,400 possible Californian licence plate combinations.
There are 26 different letters that can be chosen for each letter. There are 10 different numbers that can be chosen for each number. Since each of the numbers/digits that can be chosen for each of the six "spots" are independent events, we can multiply these combinations using the multiplicative rule of probability.combinations = (# of different digits) * (# of different digits) * (# of different digits) * (# of different letters) * (# of different letters) * (# of different letters) = 10 * 10 * 10 * 26 * 26 * 26 = 103 * 263 = 1000 * 17576 = 17,576,000 different combinations.
I suspect that you want permutations rather than combinations. The permutation ABC is different from ACB, but they are both the same combination. There are 26*26*26*10*10 or 1,757,600 possible permutations of 3 letters followed by 2 numbers. But there are ten ways of arranging 3 letters and 2 numbers: eg LLLNN, LNLNL etc. All in all, therefore, 17,576,000 permutations. However, some letters are not used so as to avoid confusion between letters and numbers: eg 0 and O. Also, some sequences are not used because they form (or suggest) inappropriate words.
(26) x (26) x (10,000) = 6,760,000