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Q: How many ounces of a 13 alcohol solution and a 42 alcohol solution must be combined to obtain 58 ounces of a 15 solution?
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How many ounces of a ten percent alcohol solution must be mixed with 6 ounces of a fifteen percent alcohol solution to make a thirteen percent alcohol solution?

4 ounces


How many ounces of a 25 percent alcohol solution must be mixed with 9 ounces of a 30 percent alcohol solution to make a 28 percent alcohol solution?

Let a be the number of ounces of 25% alcohol required. Then, 25a + (30x9) = 28(9 + a) 25a + 270 = 252 + 28a 3a = 18 a = 6 Then 6 ounces of 25% alcohol + 9 ounces of 30% alcohol produces 15 ounces of 28% alcohol.


How many ounces of the 50 percent alcohol solution should be mixed with the 1 percent alcohol solution to make 8 oz of the 20 percent alcohol solution?

Let x = ounces of 50% solution, and y = ounces of 1% solution. So that we have: 0.5x + 0.01y = 8(0.2) which is a linear equation in two variables, meaning there are infinitely many choices of mixing those solutions.


How many ounces of a 35 percent alcohol solution must be mixed with 14 ounces of a 40 percent alcohol solution to make a 37 percent alcohol solution?

.35x+.40*14=0.37(x+14) .35x=.37x-5.6+5.18 .35x=.37x-.42 -.02x=.42 x=21 check 21*.35+14*.4=7.35+5.6=12.95 12.95/(14+21)=.37 so you would need 21 ounces of 0.35 mixed in with 14 ounces of 40 % to get a 37% solution of which you would have 35 ounces


How many ounces of 20 percent saline solution must be added to 40 ounces of a 5 percent saline solution to make a 10 percent saline solution?

NOT: 15 ounces to make 10%Correct answer:Twenty ouncesCalculus:Let it be M ounces. Then:20%*(M ounce) + 5%*(40 ounce) = 10%*(M+40 ounce)20*M + 200 = 10*M + 400(20-10)*M = 400-20010M = 200M = 20

Related questions

How many ounces of a 16 alcohol solution and a 24 alcohol solution must be combined to obtain 64 of a 19 solution?

40 fl oz of the 16% solution and 24 of the other.


A pharmacist needs to obtain a 70 percent alcohol solution How many ounces of a 30 percent alcohol solution must be mixed with 40 ounces of an 80 percent alcohol solution to obtain 70 percent alcohol?

(Note: This answer assumes that the "ounces" specified are avoirdupois or other weight ounces and that percentages are by weight; otherwise possible volume changes on dilution must by considered.) The weight of pure alcohol in each solution is the product of the percentage and the total weight of the solution. Therefore, designating the unknown weight of 30 % alcohol as w, from the problem statement 0.30w + 0.80(40) = 0.70(w + 40), or 0.30w + 32 = 0.70w + 28, or 32 - 28 = w(0.70 - 0.30) or w = 4/0.40 = 10 ounces of 30 % alcohol.


How many ounces of a ten percent alcohol solution must be mixed with 6 ounces of a fifteen percent alcohol solution to make a thirteen percent alcohol solution?

4 ounces


How many ounces of a 25 percent alcohol solution must be mixed with 9 ounces of a 30 percent alcohol solution to make a 28 percent alcohol solution?

Let a be the number of ounces of 25% alcohol required. Then, 25a + (30x9) = 28(9 + a) 25a + 270 = 252 + 28a 3a = 18 a = 6 Then 6 ounces of 25% alcohol + 9 ounces of 30% alcohol produces 15 ounces of 28% alcohol.


How many ounces of 15 percent percent alcohol must be mixed with 23 percent alcohol solution to make 100 ounces?

Let x be the ounces of 15% alcohol solution. The amount of alcohol in the 15% solution is 0.15x, and the amount of alcohol in the 23% solution is 0.23(100 - x). Setting up the equation 0.15x + 0.23(100 - x) = 0.15(100) solves for x, which is approximately 38.5 ounces of the 15% alcohol solution needed.


How many ounces of the 50 percent alcohol solution should be mixed with the 1 percent alcohol solution to make 8 oz of the 20 percent alcohol solution?

Let x = ounces of 50% solution, and y = ounces of 1% solution. So that we have: 0.5x + 0.01y = 8(0.2) which is a linear equation in two variables, meaning there are infinitely many choices of mixing those solutions.


How many ounces of a 35 percent alcohol solution must be mixed with 14 ounces of a 40 percent alcohol solution to make a 37 percent alcohol solution?

.35x+.40*14=0.37(x+14) .35x=.37x-5.6+5.18 .35x=.37x-.42 -.02x=.42 x=21 check 21*.35+14*.4=7.35+5.6=12.95 12.95/(14+21)=.37 so you would need 21 ounces of 0.35 mixed in with 14 ounces of 40 % to get a 37% solution of which you would have 35 ounces


Do 1.5 ounces of liquor have more alcohol than 12 ounces of beer?

1.5 ounces of 40% alcohol is equal to 12 ounces of 5% alcohol. So no they are both the same.


Is alcohol measured in ounces?

Yes, alcohol can be measured in ounces. This is because one standard serving of alcohol is typically around 1.5 ounces.


How many ounces is serving of hard alcohol?

1.5 ounces


How many ounces of alcohol in an airplane bottle?

two ounces


Is four ounces of wine the same as four ounces of whiskey?

No, four ounces of wine and four ounces of whiskey will not have the same alcohol content. Whiskey generally has a higher alcohol by volume (ABV) than wine, so four ounces of whiskey will have more alcohol than four ounces of wine.