For one spin of a fair spinner (assuming it has a certain number of equally spaced sections, such as 4) and one toss of a coin, the total number of outcomes can be calculated by multiplying the number of outcomes for each event. If the spinner has 4 sections, there are 4 outcomes from the spin and 2 outcomes from the coin toss (heads or tails). Therefore, the total number of outcomes is 4 (from the spinner) multiplied by 2 (from the coin), resulting in 8 possible outcomes.
If you toss eight coins, there are 256 (28) different outcomes.
When you toss a 6-sided die 7 times, each toss has 6 possible outcomes. Since the tosses are independent, you can calculate the total number of outcomes by raising the number of outcomes per toss to the power of the number of tosses: (6^7). This equals 279,936 possible outcomes.
2x2x2=8 possible outcomes. In general for n tosses there are 2^n outcomes.
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If you mean roll 2 dice and spin a 2 colour spinner, there would be a total of 72 outcomes.
There are 12 possible outcomes.
Two times the number of outcomes of the spin - which is not specified in the question.
6 2 on the coin, 3 on the pointer: 2x3=6
If you toss eight coins, there are 256 (28) different outcomes.
2x2x2=8 possible outcomes. In general for n tosses there are 2^n outcomes.
24 or 16
There are 4 possible outcomes. There are 2 outcomes (heads or tails) on the first toss and 2 on the second toss. The possibilities are HH, TT, HT and TH.
There are 96 possible outcomes. A dodecahedron has 12 sides, so it has 12 possible outcomes. An octohedron has 8 sides. So for each of the 12 outcomes on the dodecahedron, the octahedron has 8 possible outcomes, hence you multiply 12 x 8 = 96.
There are 6*6*2 = 72 possible outcomes.
2^4 = 16
There are three possibilities, Heads, Tails and stand on edge
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