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Q: If you toss a coin four times how many possible outcomes are there?

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Normally there would considered to be 2⁴ = 16 possible outcomes as each outcome is one of 2 states: Head or Tails. ------------------------- There is an extremely small probability that a normal coin will end up on its edge, which mean there are 3⁴ = 81 possible outcomes. However, this probability is so small that it is ignored and normally only 2 outcomes are considered possible. As the radius to width ratio of the coin changes, the probability of the coin ending up on its edge changes, for some values being so significant that it becomes a real probability that the edge can result, and for some ratios it is almost always the edge that results and the probability of head or tails (ie ends of the cylinder that is the coin) is so small as to be ignored like the edge for a normal sized coin (cylinder).

Assuming the coins are fair, two-sided coins, and landing on their sides is not an option, there are four possible outcomes if you consider coin a having a head and coin b having a tail being a different instance from coin a being a tail and coin be having a head. Here they are; Coin A | Coin B Heads | Tails Heads | Heads Tails....| Heads Tails....| Tails

8 outcomes are possible in this situtation. You just have to multiply 4 by 2 to get the answer.

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Let H mean Head and T mean Tail. The outcomes from flipping a coin twice are the same as flipping two coins together. You might get H + H, or H + T, or T + H, or T + T. So there are four possible outcomes. They are each equally likely but if you ask, "What are the chances of throwing H + H" the answer is 1 out of 4 or 25% or 0.25, and the same for throwing T + T. However, if you ask the question, "What is the chance of throwing a H with a T the probability is 2 out of 4 because there are two ways of doing that. So the probability there is 2 out of 4, or 1 out of 2, or 50% or 0.5

Related questions

Four outcomes, three combinations.

In three flips of a fair coin, there are a total of 8 possible outcomes: T, T, T; T, T, H; T, H, T; T, H, H; H, H, H; H, H, T; H, T, H; H, T, T Of the possible outcomes, four of them (half) contain at least two heads, as can be seen by inspection. Note: In flipping a coin, there are two possible outcomes at each flipping event. The number of possible outcomes expands as a function of the number of times the coin is flipped. One flip, two possible outcomes. Two flips, four possible outcomes. Three flips, eight possible outcomes. Four flips, sixteen possible outcomes. It appears that the number of possible outcomes is a power of the number of possible outcomes, which is two. 21 = 2, 22 = 4, 23 = 8, 24 = 16, .... Looks like a pattern developing there. Welcome to this variant of permutations.

We use three coins (quarter, nickel, dime) each are flipped only once. We get 8 possible outcomes (or four outcomes as an alternative).

Let's call one coin A and the other B. omes The possible outcomes for the coins are; A heads and B tails, A tails and B heads, A and B heads, A and B tails. That's four outcomes. The possible outcomes for a single die (as in dice) are six since a die has six faces, So four times six is twenty four possible outcomes.

Out of the 16 possible outcomes for a coin tossed four times, 4 of them result in 3 Tails & 1 Head. They are: TTTH, TTHT, THTT, and HTTT.

Normally there would considered to be 2⁴ = 16 possible outcomes as each outcome is one of 2 states: Head or Tails. ------------------------- There is an extremely small probability that a normal coin will end up on its edge, which mean there are 3⁴ = 81 possible outcomes. However, this probability is so small that it is ignored and normally only 2 outcomes are considered possible. As the radius to width ratio of the coin changes, the probability of the coin ending up on its edge changes, for some values being so significant that it becomes a real probability that the edge can result, and for some ratios it is almost always the edge that results and the probability of head or tails (ie ends of the cylinder that is the coin) is so small as to be ignored like the edge for a normal sized coin (cylinder).

all headsall tails3 heads 1 tail3 tails and 1 head2h and 2ti think only 5 but that's just what i can get===============================================The above answer is correct if you disregard the order of the outcomes.If the order of the outcomes matters, then the answer is:2 x 2 x 2 x 2 = 16since each toss has two possible outcomes (assuming the coin cannot land on its side) and you repeat the toss four times.

You do 3x4!!! 3 options, and four times! Elementry!

this question is really hard!

In three tosses there can be four possible outcomes: three heads, three tails, two heads and one tail, and one head and two tails. ^^^That is wrongA coin is tossed N times. There are 2 possibilities when you toss a coin: heads and tails.So the formula is 2^N (thats to the N power)A coin tossed 3 times has 2^3=8 possible outcomes:head head headhead head tailhead tail headtail head headtail tail headhead tail tailtail head tailtail tail tailThere they are!

Assuming the coins are fair, two-sided coins, and landing on their sides is not an option, there are four possible outcomes if you consider coin a having a head and coin b having a tail being a different instance from coin a being a tail and coin be having a head. Here they are; Coin A | Coin B Heads | Tails Heads | Heads Tails....| Heads Tails....| Tails

8 outcomes are possible in this situtation. You just have to multiply 4 by 2 to get the answer.

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