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Two times the number of outcomes of the spin - which is not specified in the question.

Q: How many possible outcomes for one spin and one coin toss?

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6 2 on the coin, 3 on the pointer: 2x3=6

There are 16 possible outcomes. For the first spin, you can get red, yellow, green or blue. R, Y, G, B. Suppose the firt spin is Red, then you spin again and the final result could be one of Red-Red, Red-Yellow, Red-Green or Red-Blue. If your first spin gave a blue result, the the second would be one of Blue-Red, Blue-Yellow, Blue-Green or Blue-Blue. In all, there are 16 possible outcomes, and each is equally likely.

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Assuming each possible number on a spinner has the same probability and an unbiased die is being rolled, the answer depends on how many numbers are on the spinner, and how many times the number 4 appears on each.To find the probability, workout the probability of spinning a 4 on the spinner and the probability of rolling a 4 on the die; then as spinning the spinner has no effect on rolling the die, they are independent events and to get the probability of both happening multiply them together.The probability of success is the number of successful outcomes divided by the total number of outcomes, giving:Probability(spinning a 4) = how_many_4s_are_on_the_spinner / how_many_numbers_are_on_the_spinnerProbability(rolling a 4) = how_many_4s_are_on_the_die / how_many_numbers_are_on_the_dieProbability(spinning a 4 and rolling a 4) = Probability(spinning a 4) × Probability(rolling a 4)Examples:an octagonal spinner with the numbers 1-4 on it each twice and a tetrahedral die (as used in D&D games) with the numbers 1-4 on it→ pr(spin 4 & roll 4) = 2/8 × 1/4 = 1/16a decagonal spinner with the numbers 0-9 and a tetrahedral die with the numbers 0-3 on it→ pr(spin 4 & roll 4) = 1/10 × 0/4 = 0a decagonal spinner with the numbers 0-9 and a standard die with the numbers 1-6 on it→ pr(spin 4 & roll 4) = 1/10 × 1/6 =1/60

250

Related questions

There are 12 possible outcomes.

6 2 on the coin, 3 on the pointer: 2x3=6

There are 3 possible outcomes for each spin of the spinner. To find the total number of possible outcomes after spinning it four times, you would multiply the number of outcomes for each spin (3) by itself four times (3^4), resulting in 81 possible outcomes.

If a spinner has six possible outcomes, then there are 36 (62) permutations of outcomes from spinning it twice.

To determine the amount of possible outcomes, there must be a number of sections for each spinner

You need to know how many outcomes you have. Is the spinner composed of colors, numbers, names? What categories does the spinner have?

this question is really hard!

36

Four.Four.Four.Four.

There are 10 possibilities. For every space on the spinner you land on, there are two other outcomes (heads and tails). Say the colors are Blue, Green, Yellow, Red, and Purple. Here would be the final outcomes. Blue - heads or tails Green - heads or tails Yellow - heads or tails Red - heads or tails Purple - heads or tails

81

216... there are 6 outcomes for each cube, so 6^3 is 216