The word would be needed for a specific response, but here's a general one:
Take the factorial of the number of letters in the word, and divide that by the product of the factorials of the counts of all the unique letters in the word.
An example:
For the word "levitation", there are 10 letters, with one L, one E, one V, two Is, two Ts, one A, one O, and one N. So the solution is:
10!/(1!1!1!2!2!1!1!1!) = 10!/4 = 907,200 permutations
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10! permutations of the word "Arithmetic" may be made.
There are 7 factorial, or 5040 permutations of the letters in the word NUMBERS.
There are 195 3-letter permutations.
There are 5040.
239,500,800 12!/2! * * * * * Actually, as the word "permutation" [not permutations] has 11 letters, the answer is 11!/2! = 19,958,400