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The word would be needed for a specific response, but here's a general one:

Take the factorial of the number of letters in the word, and divide that by the product of the factorials of the counts of all the unique letters in the word.

An example:

For the word "levitation", there are 10 letters, with one L, one E, one V, two Is, two Ts, one A, one O, and one N. So the solution is:

10!/(1!1!1!2!2!1!1!1!) = 10!/4 = 907,200 permutations

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14y ago
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Q: How many permutations are there of the word?
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