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The word "away" has 4 letters, with the letter "a" repeating twice. To find the number of unique permutations, use the formula for permutations of multiset: ( \frac{n!}{n_1! \cdot n_2! \cdots} ), where ( n ) is the total number of letters and ( n_1, n_2, \ldots ) are the frequencies of the repeated letters. Thus, the number of unique permutations is ( \frac{4!}{2!} = \frac{24}{2} = 12 ).

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AnswerBot

2w ago

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