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If in a party everyone shakes everyone else and the total handshakes are 66 How many people are in the party?
Answer : 12 people. The 1st person can't shake hands with him/herself so has 11 handshakes, the 2nd person has 10 ....and so on. The total is 11 + 10 + ....+ 3 + 2 + 1 = 66. Another way is to use the formula to sum a range of consecutive integers from 1 to n. The Sum = ½n(n - 1) In this case, we can put, ½n(n - 1) = 66 then, 132 = n2 - n : n2 - n - 132 = 0 This equation can be factored, (n + 11)(n - 12) = 0 As we only require a positive integer solution, this is when n - 12 = 0, n = 12.
If you have 66 shake hands how many people in the party?
If there are n people, you have n*(n-1)/2 handshakes That gives the equation n*(n-1)/2 = 66 or n*(n-1) = 132 n2 - n - 132 = 0 (n - 12)*(n + 11) = 0 The solution to this quadratic are n = 12 or n = -11 Since the number of people cannot be negative, n must be 12.
66 inches is how many inches?
66 inches is 66 inches.
How many inches is 66 inches?
66 inches is 66 inches.
How many groups of 6 are in the number 66?
Well, isn't that a happy little question! If you have 66 and you're looking to find out how many groups of 6 you can make, you simply divide 66 by 6. When you do that, you'll find that there are 11 groups of 6 in the number 66. Just imagine all those little groups happily fitting into 66, creating a beautiful mathematical landscape!
Everybody in a party shakes hands with everybody else the total number of persons in the room are 12How many ways are there of shaking hands?
66 total handshakes are made. See related question at the bottom for the explanation.
If 12 people meet and all shake hands with each other how many handshakes will occur?
66
If theres 66 handshakes how many people are at the party?
If there are n people who shake hands with each other exactly once, it can be observed that there are n x (n-1) handshakes. Since each handshake is counted twice here,we divide this by 2. Therefore, total number of handshakes is n(n-1)/2. In the given problem, Given: Total handshakes =66 i.e n(n-1)/2=66 n2-n =132 n2-n-132=0 (n-12)(n+11)=0 n =12 or n= -11 As handshakes cannot be negative we discard 11 . Therefore answer is , 12 people.
How many 16 inch square blocks does it take to make a 10X10 patio?
66
At a party everyone shook hands with everybody else There were 66 handshakes How many people were at the party?
Each handshake involved 2 people so 12 guests: Guest A made 11 handshakes, B 10 having already been counted as an A-B handshake, C 9 etc for 2 ppl thr is 1 hand shakefor 3 thr is 3(1+2)for 4 thr is 6(1+2+3)hence12 ppl coz..sum of 1st 11 is 66...
How do you make 66 out of 6 6s?
66-66+66= 66
How many books altogether make up The Bible?
66
If in a party everyone shakes everyone else and the total handshakes are 66 How many people are in the party?
Answer : 12 people. The 1st person can't shake hands with him/herself so has 11 handshakes, the 2nd person has 10 ....and so on. The total is 11 + 10 + ....+ 3 + 2 + 1 = 66. Another way is to use the formula to sum a range of consecutive integers from 1 to n. The Sum = ½n(n - 1) In this case, we can put, ½n(n - 1) = 66 then, 132 = n2 - n : n2 - n - 132 = 0 This equation can be factored, (n + 11)(n - 12) = 0 As we only require a positive integer solution, this is when n - 12 = 0, n = 12.
How many chapters are in Make Lemonade by Virginia Euwer Wolff?
66 i think.
How many ones go into 66?
66 ones go into 66
If you have 66 shake hands how many people in the party?
If there are n people, you have n*(n-1)/2 handshakes That gives the equation n*(n-1)/2 = 66 or n*(n-1) = 132 n2 - n - 132 = 0 (n - 12)*(n + 11) = 0 The solution to this quadratic are n = 12 or n = -11 Since the number of people cannot be negative, n must be 12.
How do you make a factor tree for 66?
66 33,2 11,3,2
