The number of handshakes can be calculated using the formula for combinations, specifically ( \frac{n(n-1)}{2} ), where ( n ) is the number of people. To find the number of people that results in 66 handshakes, we can set up the equation ( \frac{n(n-1)}{2} = 66 ). Multiplying both sides by 2 gives ( n(n-1) = 132 ). Solving the quadratic equation ( n^2 - n - 132 = 0 ) yields ( n = 12 ) (the positive solution). Thus, 12 persons make up 66 handshakes.
Answer : 12 people. The 1st person can't shake hands with him/herself so has 11 handshakes, the 2nd person has 10 ....and so on. The total is 11 + 10 + ....+ 3 + 2 + 1 = 66. Another way is to use the formula to sum a range of consecutive integers from 1 to n. The Sum = ½n(n - 1) In this case, we can put, ½n(n - 1) = 66 then, 132 = n2 - n : n2 - n - 132 = 0 This equation can be factored, (n + 11)(n - 12) = 0 As we only require a positive integer solution, this is when n - 12 = 0, n = 12.
If there are n people, you have n*(n-1)/2 handshakes That gives the equation n*(n-1)/2 = 66 or n*(n-1) = 132 n2 - n - 132 = 0 (n - 12)*(n + 11) = 0 The solution to this quadratic are n = 12 or n = -11 Since the number of people cannot be negative, n must be 12.
66 inches is 66 inches.
Well, isn't that a happy little question! If you have 66 and you're looking to find out how many groups of 6 you can make, you simply divide 66 by 6. When you do that, you'll find that there are 11 groups of 6 in the number 66. Just imagine all those little groups happily fitting into 66, creating a beautiful mathematical landscape!
The answer is self evident!!!! there are 66 inches in 66(sixty six) inches.
66 total handshakes are made. See related question at the bottom for the explanation.
66
If there are n people who shake hands with each other exactly once, it can be observed that there are n x (n-1) handshakes. Since each handshake is counted twice here,we divide this by 2. Therefore, total number of handshakes is n(n-1)/2. In the given problem, Given: Total handshakes =66 i.e n(n-1)/2=66 n2-n =132 n2-n-132=0 (n-12)(n+11)=0 n =12 or n= -11 As handshakes cannot be negative we discard 11 . Therefore answer is , 12 people.
66
66 inches=5.5 feet
Each handshake involved 2 people so 12 guests: Guest A made 11 handshakes, B 10 having already been counted as an A-B handshake, C 9 etc for 2 ppl thr is 1 hand shakefor 3 thr is 3(1+2)for 4 thr is 6(1+2+3)hence12 ppl coz..sum of 1st 11 is 66...
66-66+66= 66
66
66 i think.
Answer : 12 people. The 1st person can't shake hands with him/herself so has 11 handshakes, the 2nd person has 10 ....and so on. The total is 11 + 10 + ....+ 3 + 2 + 1 = 66. Another way is to use the formula to sum a range of consecutive integers from 1 to n. The Sum = ½n(n - 1) In this case, we can put, ½n(n - 1) = 66 then, 132 = n2 - n : n2 - n - 132 = 0 This equation can be factored, (n + 11)(n - 12) = 0 As we only require a positive integer solution, this is when n - 12 = 0, n = 12.
66 ones go into 66
66 33,2 11,3,2