4
26 lower case letters + 26 uppercase letters + 10 numerals = 62 characters 624 = 14776336
If order doesn't matter, 15 combinations and if order does matter, 360 combinations are possible.
4! = 4*3*2*1 = 24 of them.
4582
256 iThink * * * * * It depends on combinations of how many. There is 1 combination of 4 letters out of 4, 4 combinations of 3 letters out of 4, 6 combinations of 2 letters out of 4, 4 combinations of 1 letter out of 4. Than makes 15 (= 24-1) in all. Well below the 256 suggested by the previous answer.
im assuming that any charcter can be a number or a letter: (24letters*10 possible numbers)^(4 digits)= 3317760000 possible combinations.
4
26 lower case letters + 26 uppercase letters + 10 numerals = 62 characters 624 = 14776336
With a Latin alphabet of 26 letters and the 10 digits 0...9, and allowing for repeats, you get: 36^4 = 36 × 36 × 36 × 36 = 1,679,616 combinations. If you were to include both lower and upper case characters, the number of possible combinations goes up (due to 26 lower case letters + 26 upper case letters + 10 digits = 62 characters to choose from): 62^4 = 14,776,336.
Say you have the letters A,B, and C. Here are all the possible combinations. * ABC * ACB * BAC * BCA * CAB * CBA So, 6 if you don't repeat any of the letters. If you DO repeat letters, then simply take the number of letters you have, (3 for instance), and multiply it to the power of the number of letters you have. So, for 3 letters, the formula would be 33 . Or if you had 4 letters it would be 44 and so on.
If order doesn't matter, 15 combinations and if order does matter, 360 combinations are possible.
2^n possible combinations
There are 210 4 digit combinations and 5040 different 4 digit codes.
12
There are 5,040 combinations.
24