It will bend at any load greater than zero. It is just a question of how much. In your example the rod will bend 0.007 inches under 10 pounds, 0.07 inches under 100 pounds, etc.
A cylinder with a diameter of 19 inches and a height of 12 inches can hold up to 14.73 gallons of water.
A round pool with a 10-foot diameter and a 3-foot depth can hold up to 1,762 gallons of water.
A hose with diameter of 6 inches has cross-sectional area of [pi*r2] = pi*(3 in)21 foot = 12 inches, so (12 in)*pi*(3 in)2 = 339.292 cubic inches per linear foot of hose.Since 1 gallon = 231 cubic inches, 339.292 cubic inches = 1.46880 gallons
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66 gallons
Their volumes are equal.
A 1-foot length of a pipe with an 1-inch internal diameter will hold pi*r2*h cubic inches where r = 0.5, h = 12 So 9.42 cubic inches.
It will bend at any load greater than zero. It is just a question of how much. In your example the rod will bend 0.007 inches under 10 pounds, 0.07 inches under 100 pounds, etc.
The answer to this question will require some simple dimensional analysis and geometry. Assuming that he pool is a round above ground pool, 18 feet in diameter and 48 inches deep you first need to calculate the area of the swimming pool in square inches and then multiply by the depth in inches to get the volume in cubic inches: The pool is an 18 foot diameter circle. The diameter in inches of the 18 foot pool is 216 inches (18 feet x 12 inches / foot) The area of a circle = pi (3.1415) x radius x radius The radius = 1/2 of the diameter The area of an 18 foot diameter pool in square inches is: 3.1415 * 108 inches * 108 inches = 36643.5 square inches The volume in cubic inches of an 18 foot diameter pool is: 36643.5 square inches x 48 inches = 1758890 cubic inches. There are 231 cubic inches in one gallon so the volume of an 18 foot diameter, 48 inch deep pool is: 1758890 / 231 = 7,614 gallons If it is a square or rectangular pool simply multiply the length x the width x the average depth.
A cylinder with a diameter of 19 inches and a height of 12 inches can hold up to 14.73 gallons of water.
area = pi * radius squared (radius = 1/2 diameter) = pi * 16 area * height = volume of a cylinder 160 feet = 1920 inches. so: pi * 16 * 1920 = 30720 pi (units is in inches cubed) or roughly 96509.7 inches cubed of water
A 100-foot hose with an inside diameter of five inches can hold 102 US gallons of water.
A 100-foot pipe with an inside diameter of 12 inches has a maximum volume of about 78.54 gallons of water.
A 56-gallon propane tank typically measures around 24 inches in diameter and 44 inches in height. It can hold up to 420 pounds of propane when filled to 80% capacity.
74.42 gallons.
A round pool with a 10-foot diameter and a 3-foot depth can hold up to 1,762 gallons of water.