The answer depends on the grain size, lithology, moisture content, and level of compaction of the sand. Generally, one cubic ft of clean (no silt/clay), dry, fine to medium sand that has been compacted to a dense, non-yielding condition will weigh about 110 lbs., while a loose fine to medium sand will weigh about 100 lbs. per cubic foot.
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Start with a conversion factor. An "old timer's" view is that a cubic foot of dry sand weighs about 125 pounds. There are 3 feet in a yard. There are 3 x 3 or 9 square feet in a square yard. There are 3 x 3 x 3 or 27 cubic feet in a cubic yard. As there are 27 cubic feet in a cubic yard and there are 125 pounds to a cubic foot of our dry sand, there are 27 x 125 pounds of dry sand per cubic yard, or 3,375 pounds of dry sand per cubic yard. (Yes, there are that many.) There are 2,240 pounds in an Imperial ton. There are 3,375 divided by 2,240 Imperial tons in a cubic yard of dry sand, or right at 1.5 Imperial tons of dry sand per cubic yard. To convert cubic yards of dry sand to Imperial tons, multiply the number of cubic yards of dry sand by 1.5 and your answer will appear. Every time.
At 12 inch per foot that is 3.14x30x30*2/12/4 = 117.75 cubic feet of sand at 100 pounds per cubic foot = 11,775 pounds (5.88 tons). Since a yard is 27 cubic feet that is 117.75/27 = 4.4 yards
sand weighs 100 pounds per cubic foot you have 100 x 50 x3/12 cu ft = 1250 cubic feet 1250 x 100 = 125,000 pounds = 125000/2000 = 62.5 tons
1 cubic meter = 35.3 cubic feet sand weighs 100 pounds per cu ft 35.3 x 100 = 3530 pounds 1 ton = 2000 pounds 3530/2000 = 1.76 tons
It depends on the density of the sand. Certainly, you are talking about 56 cubic feet, but you will need to know the bulk density of sand to figure out how much that weighs.