It has only one unique real root. There are some mathematical advantages in considering such a situation as two coincident real roots. However, given that you have to ask this question, you are still some way off getting to that level of maths - if you ever choose to do so.
The roots of the equation are [5 +/- sqrt(11)]/2 = 4.158 and 0.842
x = 2 and x = 4
The discriminant is -27 and so there are no real roots.
The discriminant of the equation ... (b2-4ac) = (225-160) ... is real and positive, so the roots are real and unequal.
You should be able to look at this equation, or use the discriminant and know that there are no real roots.
The roots are: x = -5 and x = -9
This quadratic equation has no real roots because its discriminant is less than zero.
It has roots x = 2.618 and x = 0.38197
There are no real root. The complex roots are: [-5 +/- sqrt(-3)] / 2
The roots of the equation are [5 +/- sqrt(11)]/2 = 4.158 and 0.842
If you mean b^2 -4ac then it is the discriminant of a quadratic equation. If the discriminant equals 0 then the equation has 2 equal roots. If the discriminant is greater than 0 then the equation has 2 different roots. If the discriminant is less than 0 then it has no real roots.
x = 2 and x = 4
The discriminant is -27 and so there are no real roots.
The discriminant of the equation ... (b2-4ac) = (225-160) ... is real and positive, so the roots are real and unequal.
You should be able to look at this equation, or use the discriminant and know that there are no real roots.
That is not an equation, since it doesn't have an equal sign.
It has no real roots.