thare is only 1 differint rectangles
More information is needed because it can have many dimensions such as:- 1*18 = 18 2*9 = 18 3*6 = 18
The following rectangles have a length and width that make an area of 36: 1 x 36; 2 x 18; 3 x 12; 4 x 9; 6 x 6
9
You could consider the cross as two intersecting rectangles. Calculate the area of both rectangles and the area of the intersection (overlap). Then area of cross = sum of the areas of the rectangles minus the area of the overlap.
thare is only 1 differint rectangles
Factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, and 36. So, there are 5 rectangles with an area of 36 cm^2 is 5.
Yes, it can because a 3 by 6 rectangle has the perimeter of 18 and has the area of 18! :)
More information is needed because it can have many dimensions such as:- 1*18 = 18 2*9 = 18 3*6 = 18
Three. 1 x 18, 2 x 9, 3 x 6
The answer is Infinite...The rectangles can have an infinitely small area and therefore, without a minimum value to the area of the rectangles, there will be an uncountable amount (infinite) to be able to fit into that 10 sq.in.
The following rectangles have a length and width that make an area of 36: 1 x 36; 2 x 18; 3 x 12; 4 x 9; 6 x 6
the answer is 12
Infinitely many.
3
9
You could consider the cross as two intersecting rectangles. Calculate the area of both rectangles and the area of the intersection (overlap). Then area of cross = sum of the areas of the rectangles minus the area of the overlap.