9
thare is only 1 differint rectangles
They can be: 1 by 81, 3 by 27 and 9 by 9 as integers in cm
Draw as many rectangles as the whole number you are multiplying by. Then, draw the fraction you are multiplying by in all of the rectangles. Shade in the top number in the fraction [numerator] in your rectangles. Count all the shaded in parts of all your rectangles. Leave the bottom number of your fraction [denominator] the same and put the number you got when you added the shaded parts of the rectangles on top as your denominator of the fraction. That is your answer!
18x1 9x2 6x3
9
thare is only 1 differint rectangles
The answer is Infinite...The rectangles can have an infinitely small area and therefore, without a minimum value to the area of the rectangles, there will be an uncountable amount (infinite) to be able to fit into that 10 sq.in.
They can be: 1 by 81, 3 by 27 and 9 by 9 as integers in cm
Draw as many rectangles as the whole number you are multiplying by. Then, draw the fraction you are multiplying by in all of the rectangles. Shade in the top number in the fraction [numerator] in your rectangles. Count all the shaded in parts of all your rectangles. Leave the bottom number of your fraction [denominator] the same and put the number you got when you added the shaded parts of the rectangles on top as your denominator of the fraction. That is your answer!
18x1 9x2 6x3
Infinitely many.
3
Factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, and 36. So, there are 5 rectangles with an area of 36 cm^2 is 5.
123x123=123
13
To determine the number of smaller rectangles in an area model representing 27 x 83, you would multiply the number of smaller rectangles along the length and width. In this case, there are 27 smaller rectangles along the length and 83 smaller rectangles along the width. Multiplying these numbers together gives you a total of 27 x 83 = 2241 smaller rectangles in the area model.