Infinitely many.
Let B be any number less than 6 cm, and let L = 12-B cm.
Then the perimeter of the rectangle, with length L and breadth B, is
2*[L+B] = 2*[(12-B)+B] = 2*12 = 24 cm.
There are infinitely many possible values for B, between 0 and 6 and so there are infinitely many possible rectangles.
The perimeter is 24cm
The answer is 576cm.
These are not similar rectangles so there is no obvious candidate for the ratio. Is it ratio of lengths (sides, perimeter, diameter), or ratio of area?
24cm is the perimeter.
There is an infinite number that can have that perimeter
The perimeter is 24cm
The answer is 576cm.
These are not similar rectangles so there is no obvious candidate for the ratio. Is it ratio of lengths (sides, perimeter, diameter), or ratio of area?
24cm is the perimeter.
There is an infinite number that can have that perimeter
The perimeter of the rectangle is the sum of its 4 sides.
There would be an infinite number of rectangles possible
thare is only 1 differint rectangles
perimeter = 2 (b+h) = 20 there are an infinite number of rectangles that meet the requirement
To find the number of different rectangles with a perimeter of 24 cm, we first use the formula for the perimeter ( P = 2(l + w) ), where ( l ) is the length and ( w ) is the width. Setting ( 2(l + w) = 24 ) simplifies to ( l + w = 12 ). The pairs of positive integers ( (l, w) ) that satisfy this equation are ( (1, 11), (2, 10), (3, 9), (4, 8), (5, 7), (6, 6) ). This results in 6 unique rectangles, considering length and width can be interchanged.
24cm
It is 36 cm2