Infinitely many.
Let B be any number less than 6 cm, and let L = 12-B cm.
Then the perimeter of the rectangle, with length L and breadth B, is
2*[L+B] = 2*[(12-B)+B] = 2*12 = 24 cm.
There are infinitely many possible values for B, between 0 and 6 and so there are infinitely many possible rectangles.
The perimeter is 24cm
Perimeter is 24cm
The answer is 576cm.
These are not similar rectangles so there is no obvious candidate for the ratio. Is it ratio of lengths (sides, perimeter, diameter), or ratio of area?
24cm is the perimeter.
The perimeter is 24cm
Perimeter is 24cm
The answer is 576cm.
These are not similar rectangles so there is no obvious candidate for the ratio. Is it ratio of lengths (sides, perimeter, diameter), or ratio of area?
24cm is the perimeter.
There is an infinite number that can have that perimeter
The perimeter of the rectangle is the sum of its 4 sides.
There would be an infinite number of rectangles possible
thare is only 1 differint rectangles
perimeter = 2 (b+h) = 20 there are an infinite number of rectangles that meet the requirement
It is 36 cm2
24cm