The equation ( y = x^2 - 3x + 4 ) is a quadratic function. To determine the number of roots, we can use the discriminant ( D = b^2 - 4ac ), where ( a = 1 ), ( b = -3 ), and ( c = 4 ). Calculating the discriminant gives ( D = (-3)^2 - 4(1)(4) = 9 - 16 = -7 ). Since the discriminant is negative, the equation has no real roots, indicating that the graph does not intersect the x-axis.
There are 3 cube roots of 27. There are 2 square roots of 27 ( or any real number ). There are 4 fourth roots of 27 and so on:)
4
Not sure what answer you are looking for, but here are 4 types of roots in math. First is a square roots, next is cube roots, then the nth roots, and lastly rational roots.
The square roots of 4 are -2 and 2.
-6x2 + 3x - 4 can be factored into (-x + 4)(x + 1). This equals 0 only when x is either 4 or -1. Therefore, the latter two numbers are both roots of the given function.
2
Upto 4. If the coefficients are all real, then it can have only 0, 2 or 4 real roots.
There are 3 cube roots of 27. There are 2 square roots of 27 ( or any real number ). There are 4 fourth roots of 27 and so on:)
4
Not sure what answer you are looking for, but here are 4 types of roots in math. First is a square roots, next is cube roots, then the nth roots, and lastly rational roots.
y = x2-4x+4 Since the highest degree term is 2, it must have 2 roots
None, it involves the square root of a negative number so the roots are imaginary.
The square roots of 4 are -2 and 2.
4, the same as the degree of the polynomial.
-6x2 + 3x - 4 can be factored into (-x + 4)(x + 1). This equals 0 only when x is either 4 or -1. Therefore, the latter two numbers are both roots of the given function.
In general, the answer is 4, but only 2 of them are real. For example, the 4th roots of 16 are 2, -2, 2i, and -2i.
(3x - 1)(x - 4) so roots are 1/3 and 4