Six of them.
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16.67 cm
All the possible digits (10 of them; 0-9) are multiplied by themselves by the number of digits that can be shown in the lock. (3) This is 103, or 1,000. This certainly shows why guessing is not a good way to break into a numerical lock, especially since three is a rather low number of digits for one!
1.6 x 2.4= 3.84, now we must realize 1.6cm and 2.4cm are rounded to the tenths digit (.1) so the answer must also be rounded to the tenths didgit, therefore 3.84=3.8. Now we can conclude the product has 2 significant digits due to the fact it has a 3 and 8 as a product and no zeros to make this anymore complicated.
We don't know what the base of the given number is. Since the only digits shown are 1's, the base could be anything from 2 and up. Whatever the base is, the given number is (base + 1). If " 0 0 0 0 1 1 " is a binary number (base 2), then the decimal equivalent is 3 .