32...calculated as possibillities for the first digit: 1 (because if it was 0, it would only be a 5 digit number) x 2 possibilities for the second digit x 2 possibilities for the third digit...etc. ie, 1x2x2x2x2x2=32
4 options for the first digit, 3 options for the second digit, 2 options for the third digit. Multiply the number of options together, and you find how many 3-digit numbers you can get.
210
You can select 9 numbers for the first digit, 8 numbers for the second digit, and 7numbers for the third digit; so 504 (e.g. 9*8*7) different three digit numbers can be written using the digits 1 through 9.
-5
Should be 1000. (10x10x10)
a lot
4 options for the first digit, 3 options for the second digit, 2 options for the third digit. Multiply the number of options together, and you find how many 3-digit numbers you can get.
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
-24686
2
There are 60480 numbers.
210
You can select 9 numbers for the first digit, 8 numbers for the second digit, and 7numbers for the third digit; so 504 (e.g. 9*8*7) different three digit numbers can be written using the digits 1 through 9.
ten factorial = 10! = 3,628,800
six
-5
125