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To determine how many 3-digit numbers contain the digit 8, we can consider the total number of possibilities and subtract the cases where the digit 8 is not present. There are 900 total 3-digit numbers (from 100 to 999). To find the numbers without the digit 8, we calculate the numbers that can be formed using the remaining 9 digits (0-7, 9) in each place, which is 9 x 9 x 9 = 729. Therefore, the number of 3-digit numbers that contain the digit 8 is 900 - 729 = 171.
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