If the set is of finite order, that is, it has a finite number of elements, n, then the number of subsets is 2n.
If the set has n elements, the number of subsets (the power set) has 2n members.
The number 8 is not a set and so cannot have any subsets. The set consisting of the number 8 is a set and, since it has only one element in it, it has two subsets: itself and the null set.
512 subsets
That means, figure out how many different subsets a set has. In general, if a set has n elements, it has 2n different subsets.
A fraction is a number, it is not a set. A number cannot have subsets, only a set can.
To get the number of subsets of size less than 2:Total number of subsets of a set of size N is 2NTotal number of subsets of size 1 is 100Total number of subsets of size 0 is 1Total number of subsets of size 2 is 100*99/2 = 4950Sum up: 100 + 1 + 4950 = 5051Subtract this from total subsets: 2100 - 5051 (Answer)
The number of elements. A set with n elements has 2n subsets; for example, a set with 5 elements has 25 = 32 subsets.
Only a set can have subsets, a number cannot have subsets.
If the set is of finite order, that is, it has a finite number of elements, n, then the number of subsets is 2n.
If the set has n elements, the number of subsets (the power set) has 2n members.
A finite set with N distinct elements has 2N subsets.
If the set has "n" elements, then you can make 2n different subsets. The number of subsets will always be greater than the size of the set, both for finite and for infinite sets.
The number 8 is not a set and so cannot have any subsets. The set consisting of the number 8 is a set and, since it has only one element in it, it has two subsets: itself and the null set.
No. The number of subsets of that set is strictly greater than the cardinality of that set, by Cantor's theorem. Moreover, it's consistent with ZFC that there are two sets which have different cardinality, yet have the same number of subsets.
Only a set can have subsets, a number such as -2.38 cannot have subsets.
512 subsets