8 over 5, which is the same as 8 over 3 (where 3 is calculated as 8 - 5). In other words, (8 x 7 x 6) / (1 x 2 x 3).
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5 subsets of 4 and of 1, 10 subsets of 3 and of 2 adds up to 30.
The number 8 is not a set and so cannot have any subsets. The set consisting of the number 8 is a set and, since it has only one element in it, it has two subsets: itself and the null set.
Well, honey, a set with "n" elements has 2 to the power of "n" subsets. So, if you've got a set with 5 elements, you're looking at 2 to the power of 5, which is 32 subsets. Math doesn't have to be boring, darling!
negative 8
For example, if we have a set of numbers called A which has 3 members(in our case numbers): A={2,5,6} this set has 8 subsets (2^3) which are as follow: the empty set: ∅ {2},{5},{6} {2,5},{2,6},{5,6} {2,5,6}