thenumber of subsets = 8
formula: number of subsets =
2n; wheren is thenumber of elements in the set
= 2
n= 23= 8
The subsets of 1,2,3 are:
{ }, {1}, {2}, {3}, {1,2}, {2,3}, {1,3}, {1,2,3}
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A set with 9 elements has 2^9 = 512 subsets.
Well, honey, the number of subsets in a set with 9 elements is given by 2 to the power of 9, which equals 512. So, there are 512 subsets in the set {1, 2, 3, 4, 5, 6, 7, 8, 9}. Don't worry, I double-checked it just for you.
Hi Suppose, I found that number of subsets of set S having n elements can be found by using formula 2^n, where n is number of elements of S. Let S(n) represents number of subsets of set S having n elements. S(n) = 2^n S(n+1) = 2^(n+1)
Well honey, the set {1, 2, 3, 4, 5, 6, 7, 8, 9} has 9 elements, so it will have 2^9 subsets, including the empty set and the set itself. That's a grand total of 512 subsets. Math can be sassy too, you know!
Integer Subsets: Group 1 = Negative integers: {... -3, -2, -1} Group 2 = neither negative nor positive integer: {0} Group 3 = Positive integers: {1, 2, 3 ...} Group 4 = Whole numbers: {0, 1, 2, 3 ...} Group 5 = Natural (counting) numbers: {1, 2, 3 ...} Note: Integers = {... -3, -2, -1, 0, 1, 2, 3 ...} In addition, there are other (infinitely (uncountable infinity) many) other subsets. For example, there is the set of even integers. There is also the subset {5,7}.