Assuming you don't want repetition: You have 9 options for the first position (any of the digits except 0), 9 options for the second digit (any digit, expect the digit you used in the first position), and 8 options for the third position (any digit, except the two you used before). Therefore you have 9 x 9 x 8 options. If repetition is allowed, you have 9 x 10 x 10 options.
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
For the first digit there would be 4 options For the second digit there would be 3 options for the third digit there would be 2 options Thus 4*3*2 = 24 three digit numbers can be formed if each digit can only be used once in a 3 digit number made.
There are no three didgit numbers but there are 63 three digit numbers.
Using the digits of 1345678, there are 210 three digit numbers in which no digit is repeated.
1,000 numbers000 - 999unless you include the use of decimals in which case it will be 0.00 - 9.99, 10.0-99.9, 100-999, which I believe is 2,800 numbers.
512
from 100 to 999 it is 900
27 three digit numbers from the digits 3, 5, 7 including repetitions.
There are 900 of them.
Forming three three digit numbers that use the numbers 1-9 without repeating, the highest product possible is 611,721,516. This is formed from the numbers 941, 852, and 763.
81 As there are no limits stated then you can have a number comprising a repeated single digit (such as 2222), two pairs of numbers (e.g. 2244) or three different numbers (such as 2462). The first digit can be one of any of the 3 numbers. The second digit can be one of any of the three numbers, as can the third digit and also the fourth. Then you can have 3 x 3 x 3 x 3 = 81 different 4-digit numbers using the three given numbers.
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
48 of them if digits may not be repeated. 100 if they can.
Any 3 out of 4 = 4. Each set can be arranged 6 ways so 24 different numbers.
Choose from 4 for the first number, 3 for the second number, and 2 for the third number. Therefore there are 4*3*2 = 24 three digit numbers can be formed from 3769 if each digit is used only once.
24 of them. So we have a 2 or 6 in the unit position, therefore (2)(4)(3) = 24 even three-digit numbers, can be formed.
For the first digit there would be 4 options For the second digit there would be 3 options for the third digit there would be 2 options Thus 4*3*2 = 24 three digit numbers can be formed if each digit can only be used once in a 3 digit number made.