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Assuming you don't want repetition: You have 9 options for the first position (any of the digits except 0), 9 options for the second digit (any digit, expect the digit you used in the first position), and 8 options for the third position (any digit, except the two you used before). Therefore you have 9 x 9 x 8 options. If repetition is allowed, you have 9 x 10 x 10 options.
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How many three digit numbers can be formed using the digits 873 and 6 without repetition?
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
How many even 3-digit numbers can be formed from digits 1 2 3 5 if each digit can be used only once?
For the first digit there would be 4 options For the second digit there would be 3 options for the third digit there would be 2 options Thus 4*3*2 = 24 three digit numbers can be formed if each digit can only be used once in a 3 digit number made.
How many three-digit numbers can you make from 0 6 0 9 2 0 1 2?
There are no three didgit numbers but there are 63 three digit numbers.
What are the the 3 digit numbers using 1345678?
Using the digits of 1345678, there are 210 three digit numbers in which no digit is repeated.
How many three digit counting numbers are multiples of 2 but not of 55?
There are 898 three-digit even numbers. Nine of them are multiples of 55. That leaves 889 * * * * * There are 450 three-digit even numbers and 17 of them are multiples of 55. So that leaves 433.
