Q: How many three digit numbers can you make using the digits 1 3 4 5 and 9 without repetition?

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I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24

Six (6)

If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.

9*8*7 = 504 of them.

3*2*1 = 6 of them.

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I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24

There are 7,290 different 4-digit numbers that can be formed from the digits 1-9 without repetition.

Six (6)

If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.

24 three digit numbers if repetition of digits is not allowed. 4P3 = 24.If repetition of digits is allowed then we have:For 3 repetitions, 4 three digit numbers.For 2 repetitions, 36 three digit numbers.So we have a total of 64 three digit numbers if repetition of digits is allowed.

30 without repetition (6P2) 66 with repetition (12C2)

9*8*7 = 504 of them.

3*2*1 = 6 of them.

Assuming that the first digit can't be zero: If repetition of digits is permitted: (5 x 6 x 6) = 180 numbers of 3 digits. If repetition of digits is not permitted: (5 x 5 x 4) = 100 numbers of 3 digits.

64 if repetition is allowed.24 if repetition is not allowed.

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