There are 1,368 numbers of three digits that have the number "zero" in them.
Counting positive whole numbers, 171.
100, 101, 102, 103, 104, 105, 106, 107, 108, 109, 110, 120, 130, 140, 150, 160, 170, 180, 190 - is 19
200 - 19
300 - 19
400 - 19
500 - 19
600 - 19
700 - 19
800 - 19
900 - 19
Counting negative whole numbers, then there's another 171.
Counting decimal numbers of the .001 variety there is another 171, and another 171 of the -.001 variety.
But there is also another 171 of the 1.01 variety and 171 of the -1.01 variety. And finally another 171 of the 10.1 variety and the -10.1 variety.
This works out to 8 types of three digit numbers with 171 examples in each. All having at least one zero in them, none actually ending in a zero after the decimal point.
You could have several thousand more examples, if one used the square root symbol, or did all the imaginary sets (i), or did squares, cubes, etc., or did factorials (!). And if you started to really mix and match, such as (-8.01i!), well, then it would just get silly!
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There are no three didgit numbers but there are 63 three digit numbers.
There are 900 possible three-digit numbers not beginning with 0. (Note, however, that this question does not accurately describe the restrictions on numbers that can be used as area codes.)
To solve this question, two cases must be considered:Case 1: The three-digit even number ends with 0.If the three-digit number ends with 0, then the number must be even. After the digit 0 is used, six digits remain. After any one of these six digits is chosen to be the first digit, five digits remain. To complete the number, any of the five remaining digits could be chosen to be the second digit of the number.___6___ * ___5___ * ___1___ = 30 three-digit even numbers ending in 0.1st digit-------2nd digit----3rddigit (0)Case 2: The three-digit even number does not end with 0.If the three-digit number does not end with 0, it can end with 2 or 4. Therefore, there are two possibilities for the third digit. The first digit could be any of the remaining digits, EXCEPT 0: if 0 were the first digit, it would not be a three-digit number. Therefore, there would be five possible digits for the first digit. 0 could be used as the second digit, along with the four remaining digits that were not previously used.___5___ * ___5___ * ___2___ = 50 three-digit even numbers not ending in 0.1st digit-------2nd digit-----3rddigit (0)The total number of three-digit even numbers is 80, since 30 three-digit even numbers ending in 0 plus 50 three-digit even numbers not ending in 0 equals 80.
To form a three-digit number using the digits 0-9, the first digit cannot be 0 (as it would not be a three-digit number). Thus, the first digit can be any of the digits from 1 to 9 (9 options). The second and third digits can each be any digit from 0 to 9 (10 options each). Therefore, the total number of three-digit numbers is (9 \times 10 \times 10 = 900).
It would help to know which digit. 0 appears in 9 numbers and each of the others in 18 numbers.