60
You have 5 choices for the 1st digit, 4 choices for the 2nd and 3 choices for the 3rd.
Thus, 5 x 4 x 3 = 60
99999
If you don't repeat, 20. If you do, 58.
To form a three-digit number using the digits 1-7, we can choose any of the 7 digits for each of the three places (hundreds, tens, and units). Therefore, the total number of 3-digit combinations can be calculated as (7 \times 7 \times 7), which equals 343. Thus, there are 343 different three-digit numbers that can be formed using the digits 1-7.
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
4: 1999,9199,9919,9991
8.
48 of them if digits may not be repeated. 100 if they can.
99999
If you don't repeat, 20. If you do, 58.
Assuming no repeated digits, lowest first, 20; in any order 120; Allowing repeated digits: 216
To form a three-digit number using the digits 1-7, we can choose any of the 7 digits for each of the three places (hundreds, tens, and units). Therefore, the total number of 3-digit combinations can be calculated as (7 \times 7 \times 7), which equals 343. Thus, there are 343 different three-digit numbers that can be formed using the digits 1-7.
If the digits are all different then 18. Otherwise, 192.
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
4: 1999,9199,9919,9991
15 of them.
There are 60480 numbers.
Possible solutions - using your rules are:- 11,13,17,31,33,37,71,73 &77