7 in the tens place = the number 70
7 in the thousands place = the number 7000
7000/70= 100
It is therefore 100 times bigger.
To determine how many times greater the digit in the ten thousands place is than the digit in the hundreds place, we need to understand the positional value of each digit. The positional value of a digit increases by a factor of 10 as you move from right to left in a number. Therefore, the digit in the ten thousands place is 10 times greater than the digit in the hundreds place.
The greatest six-digit number is formed by maximizing each digit while adhering to the condition that the thousands place is twice the digit in the tens place. Let the tens place be represented by ( x ); thus, the thousands place will be ( 2x ). The maximum digit for ( x ) that allows ( 2x ) to remain a single digit is 4 (since ( 2 \times 4 = 8 )). Therefore, the greatest six-digit number is 986,400, where the thousands place (8) is twice the tens place (4).
In the number 2,145,857, the digit 5 in the thousands place represents 5,000, while the digit 5 in the tens place represents 50. Therefore, the 5 in the thousands place is significantly larger, specifically 100 times greater than the 5 in the tens place.
3897
In the numeral 86784, the 8 in the ten thousands place represents 80,000, while the other 8 is in the thousands place, representing 8,000. To find how many times greater the ten thousands digit is than the thousands digit, we divide 80,000 by 8,000, which equals 10. Therefore, the 8 in the ten thousands digit is 10 times greater than the other 8.
Oh, dude, it's like super simple. The digit in the thousands place is 10 times greater than the same digit in the hundreds place. So, if you have a 3 in the thousands place, it's like 30 times greater than the 3 in the hundreds place. Math, man, it's wild.
The value of any digit in the millions place is 1,000 times the value of the same digit in the thousands place.
To determine how many times greater the digit in the ten thousands place is than the digit in the hundreds place, we need to understand the positional value of each digit. The positional value of a digit increases by a factor of 10 as you move from right to left in a number. Therefore, the digit in the ten thousands place is 10 times greater than the digit in the hundreds place.
ten thousand times greater
The greatest six-digit number is formed by maximizing each digit while adhering to the condition that the thousands place is twice the digit in the tens place. Let the tens place be represented by ( x ); thus, the thousands place will be ( 2x ). The maximum digit for ( x ) that allows ( 2x ) to remain a single digit is 4 (since ( 2 \times 4 = 8 )). Therefore, the greatest six-digit number is 986,400, where the thousands place (8) is twice the tens place (4).
In the number 2,145,857, the digit 5 in the thousands place represents 5,000, while the digit 5 in the tens place represents 50. Therefore, the 5 in the thousands place is significantly larger, specifically 100 times greater than the 5 in the tens place.
3897
The answer is in your question, 10,000.
In the decimal place value system, each digit is ten times bigger than the digit on its right
The digit in a place value is the same as the digit in the place 1000 times greater if both places represent the same digit in a number. For example, in the number 5,678, the digit '5' in the thousands place is the same as the digit '5' in the 5,000s place. However, in most numbers, this will not hold true, as each place value typically has a different digit.
The places are always the same no matter what the digits are. The value is obtained by multiplying the place times the digit. Starting from the right, the places in an 8-digit number are ones, tens, hundreds, thousands, ten thousands, hundred thousands, millions and ten millions.
1.382 OR 0.000 or 2831