7 in the tens place = the number 70
7 in the thousands place = the number 7000
7000/70= 100
It is therefore 100 times bigger.
To determine how many times greater the digit in the ten thousands place is than the digit in the hundreds place, we need to understand the positional value of each digit. The positional value of a digit increases by a factor of 10 as you move from right to left in a number. Therefore, the digit in the ten thousands place is 10 times greater than the digit in the hundreds place.
The greatest six-digit number is formed by maximizing each digit while adhering to the condition that the thousands place is twice the digit in the tens place. Let the tens place be represented by ( x ); thus, the thousands place will be ( 2x ). The maximum digit for ( x ) that allows ( 2x ) to remain a single digit is 4 (since ( 2 \times 4 = 8 )). Therefore, the greatest six-digit number is 986,400, where the thousands place (8) is twice the tens place (4).
3897
The answer is in your question, 10,000.
The digit 6 in the thousands place represents 6000, while the digit 6 in the tens place represents 60. To find out how many times greater the digit in the thousands place is compared to the digit in the tens place, we divide 6000 by 60, which equals 100. Therefore, the digit 6 in the thousands place is 100 times greater than the digit 6 in the tens place.
Oh, dude, it's like super simple. The digit in the thousands place is 10 times greater than the same digit in the hundreds place. So, if you have a 3 in the thousands place, it's like 30 times greater than the 3 in the hundreds place. Math, man, it's wild.
The value of any digit in the millions place is 1,000 times the value of the same digit in the thousands place.
To determine how many times greater the digit in the ten thousands place is than the digit in the hundreds place, we need to understand the positional value of each digit. The positional value of a digit increases by a factor of 10 as you move from right to left in a number. Therefore, the digit in the ten thousands place is 10 times greater than the digit in the hundreds place.
ten thousand times greater
The greatest six-digit number is formed by maximizing each digit while adhering to the condition that the thousands place is twice the digit in the tens place. Let the tens place be represented by ( x ); thus, the thousands place will be ( 2x ). The maximum digit for ( x ) that allows ( 2x ) to remain a single digit is 4 (since ( 2 \times 4 = 8 )). Therefore, the greatest six-digit number is 986,400, where the thousands place (8) is twice the tens place (4).
3897
The answer is in your question, 10,000.
In the decimal place value system, each digit is ten times bigger than the digit on its right
The places are always the same no matter what the digits are. The value is obtained by multiplying the place times the digit. Starting from the right, the places in an 8-digit number are ones, tens, hundreds, thousands, ten thousands, hundred thousands, millions and ten millions.
1.382 OR 0.000 or 2831
The digit 6 in the thousands place represents 6000, while the digit 6 in the tens place represents 60. To find out how many times greater the digit in the thousands place is compared to the digit in the tens place, we divide 6000 by 60, which equals 100. Therefore, the digit 6 in the thousands place is 100 times greater than the digit 6 in the tens place.
38977 is in ones place9 is in tens place (and is three times the number in thousands place)8 is in the hundreds place3 is in the thousands place7+9+8+3=27