An infinite number are possible.
Wiki User
∙ 13y ago3
bobs ur uncle
It is possible to divide a hexagon into 4 or more - up to infinitely many - triangles.
A polyhedron with two congruent triangles. There are very many possible configurations.
Well, to get that answer, there's about 30 inches in a meter, and about 2.5 cm in an inch. So, to get how many meters 99cm goes into, just multiply 30 by 2.5 and divide 99 by what you get.
2
Infinitely many.
3
bobs ur uncle
It is possible to divide a hexagon into 4 or more - up to infinitely many - triangles.
There are 16 possible triangles.
There is only one equilateral triangle with a perimeter of 60 units. Its side lengths are integers.
A polyhedron with two congruent triangles. There are very many possible configurations.
Well, to get that answer, there's about 30 inches in a meter, and about 2.5 cm in an inch. So, to get how many meters 99cm goes into, just multiply 30 by 2.5 and divide 99 by what you get.
There are an infinite number of each. I can't draw them right now, as I am busy.
33 triangles
The least number of obtuse triangles, if all possible triangles are drawn for n points in a plane, is zero. If all the n points lie in a straight line, no triangles are possible and so no obtuse triangles are able to be drawn; thus for any number n, there is a possibility that no obtuse triangles can be drawn, so the least possible number of obtuse triangles drawn is zero.