If you are Canadian (no joke), there are 618(101559956668416) ways.
If you are american, there are 518(3814697265652) ways.
Hope this helps!
You, can't.
> 6.40237371 × 1015Actually, since there are four i's and two o's, the number of distinct permutations of the letters in "oversimplification" is 18!/(4!2!) = 133,382,785,536,000.
The number of ways is 18C5 = 18!/(5!*13!) = 8,568 ways.
There are several ways to make thirty cents using different combinations of coins. The most common coins in the U.S. are pennies (1 cent), nickels (5 cents), dimes (10 cents), and quarters (25 cents). For example, you could use three dimes, six nickels, or a combination of various coins like two dimes, one nickel, and five pennies. The total number of combinations can vary, but in practice, there are 18 distinct ways to make thirty cents using these coins.
if order of beads matters than you get 18P12= 8.892185702*1012. if order doesn't matter than it's 18C12= 18564 ways to arrange the beads.
You, can't.
18
Assuming you want a rectangular array, 1 x 18, 2 x 9, or 3 x 6.
Think of the chairs as arrays. The dimensions of the arrays give you the factors of 18.
18 Chairs into equal rows - 6 x 3 2 x 9 18 x 1
18
> 6.40237371 × 1015Actually, since there are four i's and two o's, the number of distinct permutations of the letters in "oversimplification" is 18!/(4!2!) = 133,382,785,536,000.
You can have: 1 row of 36 2 rows of 18 3 rows of 12 4 rows of 9 or 6 rows of 6, so in total there are 5 ways.
18
The number of ways is 18C5 = 18!/(5!*13!) = 8,568 ways.
18 5p coins make 90p.
if order of beads matters than you get 18P12= 8.892185702*1012. if order doesn't matter than it's 18C12= 18564 ways to arrange the beads.