(15 x 14 x 13 x 12 x 11 x 10 x 9 x 8 x 7 x 6) / (10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2) =
(15 x 14 x 13 x 12 x 11) / (5 x 4 x 3 x 2) =
(14 x 13 x 12 x 11) / (8) = 3,003 different groupsof 10 mugs.
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There are 3003 ways to choose 10 mugs from a collection of 15. This can be calculated using the combination formula C(n, k) which is equal to n! / (k!(n-k)!), where n is the total number of items and k is the number of items being chosen. In this case, it would be 15! / (10!(15-10)!), which simplifies to 3003.
Assuming the 20 are all different, there are 20C11 = 20!/(11!*9!) = 167,960 ways.
Nine
24 ways
93
7C4 = 35