3 times... 3 three III
3
To determine the number of ways to complete the test, you can multiply the number of choices for each question. Since there are 3 possible answers for each of the 8 questions, the total number of ways to complete the test is (3^8). Calculating that gives (3^8 = 6,561) ways to complete the test.
The number is 30C3 = 30!/[3!*(30-3)!] = 30*29*28/(3*2*1) = 4060
24
3 times... 3 three III
3
(3+(3x3))/3=4
3 ways 6 and 1. 3 and 4. 5 and 2.
How many different ways can we arrange 9 objects taken 3 at a time?
3 ways, out of 12 possible outcomes.
The number is 30C3 = 30!/[3!*(30-3)!] = 30*29*28/(3*2*1) = 4060
24
No, in a lot more than 3 ways.No, in a lot more than 3 ways.No, in a lot more than 3 ways.No, in a lot more than 3 ways.
4
2+13 or 3+5+7
There are 4 digits. You can pick one of them as the first digit. So you can pick the first number 4 ways. Having picked the first number, the second number you can pick in only 3 ways. Having picked the first number and the second number you can pick the third number in only 2 ways. Having picked the first number and the second number and the third number you can pick the fourth number in only 1 way. So total ways of arranging 1468 would be 4 x 3 x 2 x 1 = 24