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How many ways can three students be elected from five?
Three students can be selected from 5 in (5 x 4 x 3) = 60 ways.BUT there are (3 x 2) = 6 ways to select the same 3 students.So there are only 60/6 = 10 different groups of 3 studentsthat can be selected from a pool of 5.
What is the ratio of 30 and 56?
There are 3 ways. 30/56, 30 to 56, and 30 : 56.
How many ways can a 3-person subcommittee be selected from a committee of 8 people?
-5
In a mathematics class with 30 students the teacher wants 2 different students to present the solutions to problems 3 5 on the board In how many ways can the teacher assign the problems?
There are 30 ways of selecting the first student leaving 29 ways to select the second for a total of 30 X 29 = 870 ways
How many ways can 5 CDs be selected from a stack of 12 different CDs?
The answer is 12C5 = 12*11*10*9*8/(5*4*3*2*1) = 792
How many ways can 3 books be selected from a group of 7 books?
35
3 bananas are to be selected from a group of 9 In how many ways can this be done?
im a webkin
How many ways can 3 books be selected from 5 books?
(5x4x3)/(3x2x1) = 10
In how many ways can a 3-person committee be selected from a group of 4?
-1
How many ways can a group of 3 be selected from a group with 12 members?
12C3 = 12*11*10/(3*2*1) = 220
How many ways can 8 toppings be selected to make 3 topping pizzas?
8C3 = 8*7*6/(3*2*1) = 56
How many ways can three students be elected from five?
Three students can be selected from 5 in (5 x 4 x 3) = 60 ways.BUT there are (3 x 2) = 6 ways to select the same 3 students.So there are only 60/6 = 10 different groups of 3 studentsthat can be selected from a pool of 5.
From a group of 6 boys and 3 girls an afterschool reading club of 2 boys and 2 girls is selected How many such clubs are possible?
2 boys from 6 = 6*5/2 = 15 ways 2 girls from 3 = 3*2/2 = 3 ways All in all, 15*3 = 45 ways.
How many ways can 5 people be selected out of 10?
The number of ways is 10C5 = 10!/(5!*5!) = 10*9*8*7*6/(5*4*3*2*1) = 252
What is the ratio of 30 and 56?
There are 3 ways. 30/56, 30 to 56, and 30 : 56.
How many ways can a 3-person subcommittee be selected from a committee of 8 people?
-5
How many possible ways can a committee of eight people can be selected from a group of 14 people?
There are 14C8 = 14*13*12*11*10*9/(6*5*4*3*2*1) = 3003 ways.
