To find the number of whole numbers between 10 and 200 that have exactly two identical digits, we can consider the different cases. Numbers like 11, 22, 33,...99 have two identical digits. There are 9 such numbers. For numbers like 121, 133, 144,...199, we have 9 choices for the repeated digit and 9 choices for the non-repeating digit. This gives us a total of 81 numbers. Therefore, the total number of whole numbers between 10 and 200 with exactly two identical digits is 9 + 81 = 90.
Oh, dude, let me break it down for you. So, we're looking for numbers between 10 and 200 that have exactly two identical digits, right? Well, that's like finding a needle in a haystack, but not really. There are 36 numbers that fit the bill, like 11, 22, 33, all the way up to 199. So, yeah, 36 is the magic number here.
27
it s 243..
900
900000
there are 89 twodigits in whole numbers
27
11 is the only prime number with identical digits. After 11 all numbers with identical digits can be divided by atleast 11 or 3.
it s 243..
how many numbers exactly have 4 digits ? 8900, 8999, 9000, 9999
90 of them.
There are 90 of them.
900
900000
90000 of them.
there are 89 twodigits in whole numbers
Assuming that 001, 080, etc are not allowed (that is a leading zero or two is not permitted), the smallest number with exactly three digits is 100. The largest number with exactly three digits is 999. So there are 999 - 100 + 1 = 900 numbers with exactly three digits.
90