They'll cover 105.5 square feet, with a little (2-inch by 4-inch) spot left uncovered.
when you say six inch tile, assuming that the tiles are squares with 6 inch sides. In that case, the tiles are 1/2 foot x 1/2 foot square having an area of 1/4 square feet each. To cover 10 x 8 = 80 square feet, you would need (80)/(1/4) = 320
That depends on the shape of the 280 sq. ft. area. For example, if it is a rectangle 1 foot by 280 feet, you couldn't fit a single tile into it (I assume you mean square tiles that are 20 inches on each side) because 20 inches is more than 1 foot. But assuming the area is a rectangle who sides are a multiple of 20 inches (or at least one is), we can get a pretty good estimate by converting to square inches. A sq. ft. is 12 x 12 or 144 sq. in. So 280 sq. ft. = 280 x 144 = 40,320 sq. in. Now the area of one tile is 400 sq. in. Dividing 40,320 by 400, we get 100.8. So with a suitable shaped area, we could cover most of it with 100 tiles, but there would be 320 sq. in. left over. 101 tiles would more than cover that much area, but again, to cover a given area of 280 sq. ft. with 101 tiles, the area must have a suitable shape.
Length (ft) x Width )ft) = Area (sq ft); 8 x 6 = 48 sq ft; Assuming the 6-inch tiles are square, then 4 tiles = 1 sq ft Multiply 48 sq ft x 4 tiles per sq ft to determine: 48 x 4 = 192 tiles
11,923,200 sq in. of sand.
They'll cover 105.5 square feet, with a little (2-inch by 4-inch) spot left uncovered.
when you say six inch tile, assuming that the tiles are squares with 6 inch sides. In that case, the tiles are 1/2 foot x 1/2 foot square having an area of 1/4 square feet each. To cover 10 x 8 = 80 square feet, you would need (80)/(1/4) = 320
12 square feet
An 18 inch by 18 inch tile is one and a half feet by one and a half feet, or 3/2 ft by 3/2 feet. Its area is two and a quarter square feet. (3/2 x 3/2 = 9/4). The number of tiles needed is 121 divided two and a quarter. That's 121 divided by 9/4 = 121 x 4/9 = 54 (rounding up to a whole number of tiles. But this is the minimum number of tiles needed. The real answer will depend on the shape of the area to be covered, which determines how many tiles will need to be cut and how much wastage there will be.
That depends on the shape of the 280 sq. ft. area. For example, if it is a rectangle 1 foot by 280 feet, you couldn't fit a single tile into it (I assume you mean square tiles that are 20 inches on each side) because 20 inches is more than 1 foot. But assuming the area is a rectangle who sides are a multiple of 20 inches (or at least one is), we can get a pretty good estimate by converting to square inches. A sq. ft. is 12 x 12 or 144 sq. in. So 280 sq. ft. = 280 x 144 = 40,320 sq. in. Now the area of one tile is 400 sq. in. Dividing 40,320 by 400, we get 100.8. So with a suitable shaped area, we could cover most of it with 100 tiles, but there would be 320 sq. in. left over. 101 tiles would more than cover that much area, but again, to cover a given area of 280 sq. ft. with 101 tiles, the area must have a suitable shape.
Length (ft) x Width )ft) = Area (sq ft); 8 x 6 = 48 sq ft; Assuming the 6-inch tiles are square, then 4 tiles = 1 sq ft Multiply 48 sq ft x 4 tiles per sq ft to determine: 48 x 4 = 192 tiles
11,923,200 sq in. of sand.
Depends on how much overlap there is with neighboring tiles, and if you need part-tiles at the sides etc. At least 120 at a guess.
152 sq.ft. of tile will cover the floor, you need to account for waste and defects in the tile you should also planning on keeping some extra tiles once you are done, they are often discontinued and unable to find in the event one is damaged
Without any waste you would need 25 tiles.
270 sq feet of whatever your covering it with. To find area, just multiply the 15' by the 18' and you have your answer. If your saying what you need to cover it with is 3' x 3' (such as tiles) then just divide 270 by 3 (which would mean you need 90 of them).
You would need about 1 cubic yard of topsoil to cover a 200 square foot area with 1 inch of soil.