add grout 3/16 per side
6.187 * 6.187 = 38.28 sq in
44 tiles x 38.28sq in each = 1684.27 sq in
1684.27 sq in / 144 = 11.70 sq feet
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They'll cover 105.5 square feet, with a little (2-inch by 4-inch) spot left uncovered.
when you say six inch tile, assuming that the tiles are squares with 6 inch sides. In that case, the tiles are 1/2 foot x 1/2 foot square having an area of 1/4 square feet each. To cover 10 x 8 = 80 square feet, you would need (80)/(1/4) = 320
That depends on the shape of the 280 sq. ft. area. For example, if it is a rectangle 1 foot by 280 feet, you couldn't fit a single tile into it (I assume you mean square tiles that are 20 inches on each side) because 20 inches is more than 1 foot. But assuming the area is a rectangle who sides are a multiple of 20 inches (or at least one is), we can get a pretty good estimate by converting to square inches. A sq. ft. is 12 x 12 or 144 sq. in. So 280 sq. ft. = 280 x 144 = 40,320 sq. in. Now the area of one tile is 400 sq. in. Dividing 40,320 by 400, we get 100.8. So with a suitable shaped area, we could cover most of it with 100 tiles, but there would be 320 sq. in. left over. 101 tiles would more than cover that much area, but again, to cover a given area of 280 sq. ft. with 101 tiles, the area must have a suitable shape.
Length (ft) x Width )ft) = Area (sq ft); 8 x 6 = 48 sq ft; Assuming the 6-inch tiles are square, then 4 tiles = 1 sq ft Multiply 48 sq ft x 4 tiles per sq ft to determine: 48 x 4 = 192 tiles
11,923,200 sq in. of sand.