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How many gallons of a 9 percent salt solution must be mixed with 25 gallons of a 31 percent solution to obtain a 20 percent solution?
25 gallons
How much is 25 percent in 36?
9 is 25 percent of 36.
What number is 25 percent of 180 answers and solution?
25% of 180 = 45= 25% * 180= 0.25 * 180= 45
How much of world is land in percent?
25 percent
How much is 25 percent off of 119.50 be?
25 percent off of 119.50 is 29.875.
How much water must be added to 40 ml of a 25 percent by weight solution to make a 2 percent by weight solution?
About 80ml of water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution.
A chemist has one solution which is 50 percent acid and a second solution which is 25 percent acid how much of each should be mixed to make a 10 liters of a 40 percent acid solution?
6 litres of 50% + 4 litres of 25%
How many gallons of a 9 percent salt solution must be mixed with 25 gallons of a 31 percent solution to obtain a 20 percent solution?
25 gallons
Mary is experimenting with chemicals in the laboratory She mixes a solution that is 10 percent acid with a solution that is 25 percent acid How much of the 10 percent acid solution will be needed to m?
16 2/3 liters
How do you dilute 25 percent Glucose and Glutamic acid?
To dilute a 25% glucose and glutamic acid solution, you would mix the solution with an appropriate amount of water. The exact amount of water needed will depend on the desired final concentration of the solution. Calculate the amount of water needed based on the volume and concentration of the original solution.
How many ml should be added to 100ml of a 25 percent solution to get produce a 20 percent solution?
add 25ml more of solution x * 20 = 100 * 25 x = 25
How much water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution?
To make a 2% solution from a 25% solution, you need to dilute it. Let x ml be the amount of water needed. Using the equation for mass balance: 0.25(40) = 0.02(40 + x), solve for x to find that x = 875 ml of water needs to be added.
How much water must be added to 12 grams of a 90 percent iodine solution to produce a 25 percent iodine solution?
12*(90%)=10.8=X*.25 10.8/.25=X=43.2 43.2-12=31.2 31.2 grams of water must be added
What is the solution of 5.6 is 25 percent of what number?
22.4
How many liters of a 20 percent solution of acid should be added to 10 liters of a 30 percent solution of acid to obtain a 25 percent solution?
10 liters.
Which is 25 percent of 50?
12.5 ------------------- Solution Method: ? = 25% of 50 ? = 25%/100 * 50 ? = .25 * 50 ? = 12.5 <-- this is your answer ====== Answer 1: 25 percent of 50 is 12.5.
How many grams (of mass m) of glucose are in 205 mL of a 5.50 (mv) glucose solution?
To find the mass of glucose in the solution, we first need to calculate the volume of glucose in the solution. Using the formula m = V x mv, we find that the mass of glucose (m) in 205 mL of a 5.50 mv glucose solution is approximately 11.28 grams.
