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How much heat does it take to change 92 pounds of water at 137 degrees F to 119 degrees F?
Wiki User
∙ 12y ago
Use 1 BTU = 1 lb of water 1° F.
Quantity = 92 lbs
Temp change = (137° - 119°) = 18° F.
92 x 18 = 1,656 .
It doesn't 'take' any heat to do the job. Since you're allowing the water to cool,
from 137° to 119° , the water will release 1,656 BTU of heat as that happens.
Then you can gather up the heat and take it away to do something else with it.
Wiki User
∙ 12y ago
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How many Btu are required to change 600 pounds of water at 75 degrees F to steam at 212 degrees F?
1 BTU is required to raise 1lb of water 1 degree F in 1 hour. 212-75=137 degrees 600 lbs water x 137 degrees= 82,200 BTU's required to change 75 degree water to 212 degree water. To change 212 degree water to 212 degree steam it requires 970 btu's (latent heat of vaporization) per lb of water 970 btu x 600 lbs water = 582,000 btu Answer - 582,000 btu+ 82,200 btu = 664,200 btu's
The amount of heat removed to lower the temperature of 15 pounds of water from 48 degrees f to 39 degrees f is?
135 btu
How much heat is necessary to change 30 grams of water at 40 degrees celsius into water at 60 degrees celsius?
The idea here is to: * Look up the specific heat of water. * Multiply the mass, times the temperature difference, times the specific heat of water. You may need to do some unit conversions first; specifically, if the specific heat is given per kilogram, you can convert the grams to kilograms.
How many calories are needed to change 1 gram of 100 degrees Celsius boiling water to 100 degrees Celsius steam?
This is the latent heat of vaporisation of water, which at standard pressure, is 539 calories (per gram).
How much heat is required to change 0.2kg of ice at -5 degrees to water at 5 degrees?
Heat required for this transition is given as the the sum of three heatsheat required for heating the ice from -5 degree Celsius +latent heat(conversion of ice at zero degree to water at zero degrees)+heat required to heat the water from 0 to 5 degree CelsiusHeating of ice=m x s x delta T,where m is the mass ,s is the specific heat of ice=200x0.5x5=500calmelting of ice=mxlatent heat=200x80=16,000calHeating of water=m x s x delta T,where m is the mass ,s is the specific heat of water =200x1x5=1000calTotal heat required=500+16,000+1000=17,500 cal
How much heat from 5 pounds of 232 degrees steam to create 5 pounds of 162 degrees of water?
To calculate the heat required to cool steam to water at a lower temperature, you can use the formula: Q = mcΔT Where: Q = heat energy m = mass c = specific heat capacity ΔT = change in temperature Given: m = 5 pounds ΔT = (232 - 162) = 70 degrees F Specific heat capacity of water = 1 cal/g°C Convert pounds to grams: 1 pound ≈ 453.592 grams Now, plug in the values into the formula to calculate the heat energy.
How many BTU will it take to change 10 pounds of ice at 20 degrees to steam at 220 degrees?
To change 10 pounds of ice at 20 degrees Fahrenheit to steam at 220 degrees Fahrenheit, you need to supply enough energy to first melt the ice, then heat the water to the boiling point, and finally convert it to steam. This process requires approximately 180 BTUs per pound of ice to melt it, 180 BTUs per pound of water to heat it to the boiling point, and then 970 BTUs per pound of water to convert it to steam. So, for 10 pounds of ice, the total BTUs required would be around 18,300 BTUs.
What is required to change the state of water?
To change the state of water from solid (ice) to liquid (water), heat must be added to increase the temperature above 0 degrees Celsius. To change water from liquid to gas (water vapor), heat must be added to increase the temperature above 100 degrees Celsius.
How many Btu's need to be removed from lb of water to change degrees to degrees?
To change the temperature of water by one degree Fahrenheit, 1 Btu of heat must be added or removed from 1 pound of water.
How much energy is needed to change 125g of ice at -32.9 degrees to water at 75 degrees?
To calculate the energy needed to change ice at -32.9 degrees to water at 75 degrees, you need to consider the energy required for three steps: Heating ice from -32.9 degrees to 0 degrees (specific heat capacity of ice) Melting ice at 0 degrees into water at 0 degrees (latent heat of fusion of ice) Heating water from 0 degrees to 75 degrees (specific heat capacity of water) Once you have the energy needed for each step, you can add them together to find the total energy required.
How much heat must be transferred to liquid water to change the waters temperature from 27 degrees Celsius to 32 degrees Celsius?
To change the temperature of water from 27ºC to 32ºC will depend on the mass of water that is present. Obviously, the more water, the more heat it will take. This can be calculated as follows:q = heat = mC∆T where m is the mass of water; C is sp. heat = 4.184 J/g/deg and ∆T is 5ºC (change in temp).
When water at 212 degrees boils it is only absorbing latent heat True or false?
False. When water reaches 212 degrees Fahrenheit (100 degrees Celsius) and boils, it is absorbing both sensible heat (temperature increase) and latent heat (phase change from liquid to gas).
How much more heat needs to be added to water at 100 degrees centigrade in order to change it to steam?
Heat required to have such a change of state is called latent heat. If L J/kg is the latent heat per kg of water then for M kg of water we need M* L joule of heat energy
What is the name of heat energy that changes ice into water and water into steam?
Latent heat is the measurement of energy needed to change the state of a substance at its melting point or boiling point. The latent heat of fusion of water is the amount of energy needed to change a fixed amount of water from a solid to liquid at 0 degrees C. this works out to be more than 800KJ of heat energy. The latent heat of vaporization of water is the amount of energy needed to change a fixed amount of water from a liquid to a gas at 100 degrees C. this is more than 1200KJ of heat needed to be absorbed.
How much heat would it take to raise 10 pounds of water from 40 degrees to 41 degrees f?
the answer is 200 Btu. the formula is weight x specific heat x temperature difference so we have 10 pounds x 1.00 x 20 10 for 10 pounds of water the specific heat of water is 1.00 and the temperature difference would be 70-50= 20
What happens when heat is added to something?
Then it will either get hotter, or change its phase (for example, ice at zero degrees will convert to water, also at zero degrees).
How many Btu are required to change 600 pounds of water at 75 degrees F to steam at 212 degrees F?
1 BTU is required to raise 1lb of water 1 degree F in 1 hour. 212-75=137 degrees 600 lbs water x 137 degrees= 82,200 BTU's required to change 75 degree water to 212 degree water. To change 212 degree water to 212 degree steam it requires 970 btu's (latent heat of vaporization) per lb of water 970 btu x 600 lbs water = 582,000 btu Answer - 582,000 btu+ 82,200 btu = 664,200 btu's
