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A 50 ml solution that is 10% acid will consist of 5 ml of acid (10% of the volume) and 45 ml of water (90% of the volume). You're not adding any water, but you want to add enough acid to make a solution that is 50% acid and 50% water. You will need to have a total of 45 ml of acid in the mixture to make it a 50/50 solution, since the amount of water is also 45 ml. You have 5 ml in there already, so you would need to add 40 ml of acid. That would make a total 90 ml solution that is 50% water (45 ml) and 50% acid (45 ml).

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How much pure acid should be mixed with 5 gallons of 70 percent acid solution in order to get a 90 percent acid solution?

x=45


How much pure acid should be mixed with 6 gallons of a 50 percent acid solution in order to get an 80 percent acid solution?

50% acid in a 6 gallon solution means that 3 gallons are acid. 9 gallons more acid will give you a total of 12 gallons of acid in a 15 gallon solution. 12 is 80% of 15.


How much pure acid should be mixed with 5 gallons of a 20 percent acid solution to get a 50 percent acid solution?

x = amount of acid to add. y = final volume. 5 gal + x = y original amount of acid + acid added = final amount of acid (5 X .2) + x = O.5y Subtract the second equation from the first one. 5 - 1 + x - x = y - 0.5y 4 = 0.5y 8 = y Therefore the final volume is 8 gallons. 5 gal + x = 8 x = 3 gal. the amount of pure acid to add. Check the answer 5 X .2 = 1 gal of acid in original solution. 3 gallons added = 4 gallons total acid in solution. 4 gallons total acid in final solution of 8 gallons total solution = 50% acid.


Is it possible to mix a 10 percent acid solution and a 40 percent acid solution to obtain a 60 percent acid solution?

No. The reulting concentration (percent) must be between the two components. So, with the two acids you are mixing, you cannot get an acid that is less than 10% or more than 40%


How many liters of a 90 percent acid solution must be mixed with a 15 percent acid solution to get 600 L of a 80 percent solution?

Mixing 80 liters of 15% solution and 520 liters of 90% solution will give 600 liters of 80% solution.

Related Questions

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How much pure acid should be mixed with 5 gallons of 70 percent acid solution in order to get a 90 percent acid solution?

x=45


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How much of an 18 percent solution of sulfuric acid should be added to 360 ml of a 10 percent solution to obtain a 15 percent solution?

To determine the amount of 18% solution to add: Let x = volume of 18% solution to be added. 0.18x + 0.10(360) = 0.15(x + 360) Solving for x, you would need to add 75 ml of the 18% solution to the 360 ml of 10% solution to obtain a 15% solution.


If you have a 300ml of a 15 percent hydrochloric acid solution in dilute the solution to 1000ml with sterile water what percent should appear on the label?

The final concentration of the hydrochloric acid solution would be 5% after dilution. Therefore, the label should indicate that the solution is a 5% hydrochloric acid solution.


A chemist has one solution that is 80 percent acid and another solution that is 30 percent acid How much of the second 30 percent solution is needed to make a 400 L solution that is 62 percent acid?

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How much pure acid should be mixed with 6 gallons of a 50 percent acid solution in order to get an 80 percent acid solution?

50% acid in a 6 gallon solution means that 3 gallons are acid. 9 gallons more acid will give you a total of 12 gallons of acid in a 15 gallon solution. 12 is 80% of 15.


How many liters of a 50 percent alcohol solution must be mixed with 40 liters of a 90 percent solution to get a 60 percent solution?

mary mixed 2l of an 80% acid solution with 6l of a 20% acid solution. what was the percent of acid in the resulting mixture


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A chemist is making 200 L of a solution that is 62 percent acid He is mixing an 80 percent acid solution with a 30 percent acid solution How much of the 80 percent acid solution will he use?

The chemist will use 100 liters of the 80% acid solution and 100 liters of the 30% acid solution to make a 200-liter solution that is 62% acid. The amount of acid in the 80% solution will be 0.8 * 100 = 80 liters, and in the 30% solution, it will be 0.3 * 100 = 30 liters.


How much acid and chlorine should be added to a 5000 liter swimming pool?

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