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18 ft * 18 ft * 2 inches = 6 yards * 6 yards * 2/36 yards = 2 cubic yards.

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Q: How much sand is needed to cover 18 ft x18 ft at 2 inches deep?

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An area 10 foot x 10 foot is 100 square feet. 100 cubic feet of sand would cover it with a one foot deep layer of sand. If the sand needs to be 6 inches deep, then 50 cubic feet are be needed, or 25 cubic feet if the sand is to be 3 inches thick.

84 cubic inches!

That depends upon how deep the soil bed is and how much moisture is in the topsoil. But here are some ballpark numbers for you: A yard of soil will cover a 10' by 10' area to a depth of three inches. In other words, figure a third of a yard per 100 square feet for every inch of depth. Length x width x # of inches deep divided by 324 = the number of cubic yards needed for that task.

10*13*3 = 390 cubic inches.

3 inches = .25 feet400 square feet X .25 feet = 100 cubic feet100 cubic feet / 27 cubic feet per cubic yard = 3.7 yards

Related questions

For 1 foot deep, 400 cu ft. For 3 inches deep, 100 cu ft.

You will need 1500 cubic feet.

To give you an answer, we need to know how wide, how long and how deep. You gave us 2 of the 3 numbers we need. No answer for you.

2.37 cubic yards of stone for every 3 inches deep it needs to be

3000 sq ft * 4 inches = 1000 cubic feet.

Plan on about 2.2 cubic yards (2.8 tons) of gravel.

630 cubic inches

54sqare feet

Usually a cubic yard will cover 15 square yards at 3 inches deep so I would reckon on 22 cubic yards. Hold on that I've got that wrong it's 2 cubic yards .Sorry.

About a ton.

15 square yards at 3 inches deep.

2 inches = 1/6 foot Volume = 3,500/6 = 5831/3 cubic feet = 21.605 cubic yards

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